**Problem 11:**Trevor has 6 books on his summer reading list. He wants to choose 3 books to pack them in his suitcase for reading during vacation. How many different choices are possible? SHOW WORK**Solution:**To determine the number of ways Trevor can choose 3 books out of 6, we can use the concept of combinations. The formula for combinations is given by:\[ C(n, k) = \frac{n!}{k!(n-k)!} \]where $ n $ is the total number of items, $ k $ is the number of items to choose, and $ ! $ denotes factorial (the product of all positive integers up to that number).In this problem, $ n = 6 $ and $ k = 3 $. Plugging these values into the formula, we have:\[ C(6, 3) = \frac{6!}{3!(6-3)!} \]\[ C(6, 3) = \frac{6!}{3! \cdot 3!} \]\[ C(6, 3) = \frac{6 \times 5 \times 4 \times 3!}{3! \times 3!} \]\[ C(6, 3) = \frac{6 \times 5 \times 4}{3 \times 2 \times 1} \]\[ C(6, 3) = \frac{120}{6} \]\[ C(6, 3) = 20 \]Therefore, Trevor has 20 different choices for selecting 3 books out of his 6-book reading list.

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Answered: Trevor has 6 books on his summer…

Trevor has 6 books on his summer reading list. He wants to choose 3 books to pack them in his suitcase for reading during vacation. How many different choices are possible? SHOW WORK

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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