tree. Assume that has a normal distribution wi mean of 136.8 ft and a standard deviation of 8.1 ft. A tree of this type grows in my backyard, and it stands 141.7 feet tall. Find the probability that the heig of a randomly selected tree is as tall as mine or shorter. My neighbor also has a tree of this type growing in her backyard, but hers stands 149.8 feet tall. Find the probability that the full height of a randomly selected tree is at least as tall as hers. Enter your answers as decimals accurate to 4 decimal places. Submit Question MacBook Air

MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
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3
Let X represent the full height of a certain species of tree. Assume that X has a normal distribution with a
mean of 136.8 ft and a standard deviation of 8.1 ft.
A tree of this type grows in my backyard, and it stands 141.7 feet tall. Find the probability that the height
of a randomly selected tree is as tall as mine or shorter.
My neighbor also has a tree of this type growing in her backyard, but hers stands 149.8 feet tall. Find the
probability that the full height of a randomly selected tree is at least as tall as hers.
Enter your answers as decimals accurate to 4 decimal places.
Submit Question
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Transcribed Image Text:3 Let X represent the full height of a certain species of tree. Assume that X has a normal distribution with a mean of 136.8 ft and a standard deviation of 8.1 ft. A tree of this type grows in my backyard, and it stands 141.7 feet tall. Find the probability that the height of a randomly selected tree is as tall as mine or shorter. My neighbor also has a tree of this type growing in her backyard, but hers stands 149.8 feet tall. Find the probability that the full height of a randomly selected tree is at least as tall as hers. Enter your answers as decimals accurate to 4 decimal places. Submit Question 3.0 E D FFB $ 4 70 F in de % FSS T G MacBook Air Y & 7 H *** 8 U UI J F9 K
Expert Solution
Step 1

Given that

Mean=136.8, Standard deviations=8.1

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