Treatments Error k-1 =3 N-k=716 SSTR = 212.9379 SSE 1,969.4932 MSTR = MSE = SSTr k-1 212.9379 SSE N-k 1,969.4932
Treatments Error k-1 =3 N-k=716 SSTR = 212.9379 SSE 1,969.4932 MSTR = MSE = SSTr k-1 212.9379 SSE N-k 1,969.4932
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![Now that the degrees of freedom and sum of squares columns have been determined, we can calculate the values in the mean square column. Calculate the mean square for treatments, MSTr, and mean square for error, MSE,
and place them in the ANOVA table, rounding the results to three decimal places.
Degrees of Freedom
Source of Variation
Treatments
Error
k - 1 = 3
N - k = 716
Sum of Squares
SSTR = 212.9379
SSE = 1,969.4932
Mean Square
MSTR =
=
MSE =
SSTr
k - 1
212.9379
SSE
N-K
1,969.4932
F](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8930b4ba-63a5-417a-9be8-9037e4977d85%2Fea32add6-d6db-4522-a4a7-deaab917cc97%2Fx287lg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Now that the degrees of freedom and sum of squares columns have been determined, we can calculate the values in the mean square column. Calculate the mean square for treatments, MSTr, and mean square for error, MSE,
and place them in the ANOVA table, rounding the results to three decimal places.
Degrees of Freedom
Source of Variation
Treatments
Error
k - 1 = 3
N - k = 716
Sum of Squares
SSTR = 212.9379
SSE = 1,969.4932
Mean Square
MSTR =
=
MSE =
SSTr
k - 1
212.9379
SSE
N-K
1,969.4932
F
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