Treatment of the polymer shown below with aqueous 6 molar hydrochloric acid at 80 °C leads to which products? Check the correct answer. HN 0 1.1,6 Hexanediol, carbon dioxide, and the dihydrochloride of the aromatic diamine. O 2 A disocyanate and 1,6-hexanediol. 03.1,6-Hexanediol, phosgene (COCz, and the dihydrochloride of the aromatic diamine. 0 4. The aromatic diamine, urethane, and 1,6-hexanediol.

Treatment of the polymer shown below with aqueous 6 molar hydrochloric acid at 80 °C leads to which products? Check the correct answer. HN 0 1.1,6 Hexanediol, carbon dioxide, and the dihydrochloride of the aromatic diamine. O 2 A disocyanate and 1,6-hexanediol. 03.1,6-Hexanediol, phosgene (COCz, and the dihydrochloride of the aromatic diamine. 0 4. The aromatic diamine, urethane, and 1,6-hexanediol.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Types of Polymers on the basis of Method of Preparation

Question

Treatment of the polymer shown below with aqueous 6 molar hydrochloric acid at 80 °C leads to which products? Check the correct answer.
HN'
O 1.1,6-Hexanediol, carbon dioxide, and the dihydrochloride of the aromatic diamine.
2. A diisocyanate and 1,6-hexanediol.
O 3. 1,6-Hexanediol, phosgene (COC2), and the dihydrochloride of the aromatic diamine.
O 4. The aromatic diamine, urethane, and 1,6-hexanediol.

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