Treatment of hydroxylamine (H₂NOH) with an excess of Fe (III) results in the formation of N₂O and an equivalent amount of Fe (II): 2 H₂NOH + 4 Fe³+ N₂O(g) + 4 Fe2+ + 14 H+ + H₂O Calculate the molar concentration of an H₂NOH solution if the Fe (II) produced by treatment of a 36.22 -mL aliquot required 15.99 mL of 0.0784 M K2Cr207. Cr₂O72- + 6 Fe2+ +12 H+ 2 Cr³+ + 6 Fe 3+ + 7 H₂O

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Question 3
Treatment of hydroxylamine (H₂NOH) with an excess of Fe (III) results in the formation of N₂O and an equivalent amount of Fe (II):
2 H₂NOH + 4 Fe³+ N₂O(g) + 4 Fe²+ + 14 H+ + H₂O
Calculate the molar concentration of an H₂NOH solution if the Fe (II) produced by treatment of a 36.22 -mL aliquot required 15.99 mL of 0.0784 M K2Cr2O7.
2-
3+
Cr₂O7²- + 6 Fe²+ + 12 H+ 2 Cr³+ + 6 Fe
Express your answer with 3 decimal places
+ 7 H₂O
Transcribed Image Text:Question 3 Treatment of hydroxylamine (H₂NOH) with an excess of Fe (III) results in the formation of N₂O and an equivalent amount of Fe (II): 2 H₂NOH + 4 Fe³+ N₂O(g) + 4 Fe²+ + 14 H+ + H₂O Calculate the molar concentration of an H₂NOH solution if the Fe (II) produced by treatment of a 36.22 -mL aliquot required 15.99 mL of 0.0784 M K2Cr2O7. 2- 3+ Cr₂O7²- + 6 Fe²+ + 12 H+ 2 Cr³+ + 6 Fe Express your answer with 3 decimal places + 7 H₂O
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