Travel to Outer Space A CBS News/New York Times poll found that 329 out of 763 randomly selected adults said they would travel to outer space in their lifetime, given the chance. Estimate the true proportion of adults who would like to travel to outer space with 97% accuracy. Round your answers to at least three decimal places.

MATLAB: An Introduction with Applications
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Travel to Outer Space A CBS News/New York Times poll found that 329 out
of 763 randomly selected adults said they would travel to outer space in their
lifetime, given the chance. Estimate the true proportion of adults who would
like to travel to outer space with 97% accuracy. Round your answers to at
least three decimal places.
<p<
Transcribed Image Text:Travel to Outer Space A CBS News/New York Times poll found that 329 out of 763 randomly selected adults said they would travel to outer space in their lifetime, given the chance. Estimate the true proportion of adults who would like to travel to outer space with 97% accuracy. Round your answers to at least three decimal places. <p<
Sample Question
Travel to Outer Space A CBS News/New York
Times poll found that 329 out of 763 randomly
selected adults said they would travel to outer
space in their lifetime, given the chance.
Estimate the true proportion of adults who
would like to travel to outer space with 92%
accuracy. Round your answers to at least three
decimal places.
Explanation
Formula for a Specific Confidence
Interval for a Proportion
M
pq
pg
P-²α/² √
<p<p +²a/2\
n
n
when n p and nq are each greater
than or equal to 5.
Since a 1-0.92-0.08, Za/2=1.75.
Find and .
329
p= =
n
763
= 0.431
q=1-p=1-0.431
= 0.569
Calculate the confidence interval.
Za/2
pq
n
(0.431) (0.569)
0.431 1.75
<p<0.431 +1.75
763
0.431 0.031 <p<0.431+0.031
0.400<p<0.462
Hence, we can be 92% confident that the
proportion of adults who would go into outer
space is between 40.0% and 46.2%, based on a
sample of 763 people.
pq
n
(0.431) (0.569)
763
<p<p +²a/2
Transcribed Image Text:Sample Question Travel to Outer Space A CBS News/New York Times poll found that 329 out of 763 randomly selected adults said they would travel to outer space in their lifetime, given the chance. Estimate the true proportion of adults who would like to travel to outer space with 92% accuracy. Round your answers to at least three decimal places. Explanation Formula for a Specific Confidence Interval for a Proportion M pq pg P-²α/² √ <p<p +²a/2\ n n when n p and nq are each greater than or equal to 5. Since a 1-0.92-0.08, Za/2=1.75. Find and . 329 p= = n 763 = 0.431 q=1-p=1-0.431 = 0.569 Calculate the confidence interval. Za/2 pq n (0.431) (0.569) 0.431 1.75 <p<0.431 +1.75 763 0.431 0.031 <p<0.431+0.031 0.400<p<0.462 Hence, we can be 92% confident that the proportion of adults who would go into outer space is between 40.0% and 46.2%, based on a sample of 763 people. pq n (0.431) (0.569) 763 <p<p +²a/2
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