Travel to Outer Space A CBS News/New York Times poll found that 329 out of 763 randomly selected adults said they would travel to outer space in their lifetime, given the chance. Estimate the true proportion of adults who would like to travel to outer space with 97% accuracy. Round your answers to at least three decimal places.
Travel to Outer Space A CBS News/New York Times poll found that 329 out of 763 randomly selected adults said they would travel to outer space in their lifetime, given the chance. Estimate the true proportion of adults who would like to travel to outer space with 97% accuracy. Round your answers to at least three decimal places.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Travel to Outer Space A CBS News/New York Times poll found that 329 out
of 763 randomly selected adults said they would travel to outer space in their
lifetime, given the chance. Estimate the true proportion of adults who would
like to travel to outer space with 97% accuracy. Round your answers to at
least three decimal places.
<p<
Transcribed Image Text:Sample Question
Travel to Outer Space A CBS News/New York
Times poll found that 329 out of 763 randomly
selected adults said they would travel to outer
space in their lifetime, given the chance.
Estimate the true proportion of adults who
would like to travel to outer space with 92%
accuracy. Round your answers to at least three
decimal places.
Explanation
Formula for a Specific Confidence
Interval for a Proportion
M
pq
pg
P-²α/² √
<p<p +²a/2\
n
n
when n p and nq are each greater
than or equal to 5.
Since a 1-0.92-0.08, Za/2=1.75.
Find and .
329
p= =
n
763
= 0.431
q=1-p=1-0.431
= 0.569
Calculate the confidence interval.
Za/2
pq
n
(0.431) (0.569)
0.431 1.75
<p<0.431 +1.75
763
0.431 0.031 <p<0.431+0.031
0.400<p<0.462
Hence, we can be 92% confident that the
proportion of adults who would go into outer
space is between 40.0% and 46.2%, based on a
sample of 763 people.
pq
n
(0.431) (0.569)
763
<p<p +²a/2
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