Transverse waves propagate at 43.2 m/s in a string that is subjected to a tension of 60.5 N. If the string is 16.5 m long, what is its mass O 0.535 kg O 0.621 kg 0.225 kg O 0.38 kg

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Chapter1: Units, Trigonometry. And Vectors
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Q14

**Question:**

Transverse waves propagate at 43.2 m/s in a string that is subjected to a tension of 60.5 N. If the string is 16.5 m long, what is its mass?

**Options:**

- A) 0.535 kg
- B) 0.621 kg
- C) 0.225 kg
- D) 0.38 kg

**Explanation:**

To solve this problem, use the formula for the speed of a wave on a string: 

\[ v = \sqrt{\frac{T}{\mu}} \]

where:
- \( v \) is the wave speed (43.2 m/s),
- \( T \) is the tension in the string (60.5 N),
- \( \mu \) is the linear mass density of the string. 

First, solve for \( \mu \):

\[ \mu = \frac{T}{v^2} \]

Calculate \( \mu \) using the given values:

\[ \mu = \frac{60.5}{(43.2)^2} \]

Then, calculate the mass (\( m \)) of the string using:

\[ m = \mu \times L \]

where \( L \) is the length of the string (16.5 m).

This will give you the mass of the string, matching one of the provided options.
Transcribed Image Text:**Question:** Transverse waves propagate at 43.2 m/s in a string that is subjected to a tension of 60.5 N. If the string is 16.5 m long, what is its mass? **Options:** - A) 0.535 kg - B) 0.621 kg - C) 0.225 kg - D) 0.38 kg **Explanation:** To solve this problem, use the formula for the speed of a wave on a string: \[ v = \sqrt{\frac{T}{\mu}} \] where: - \( v \) is the wave speed (43.2 m/s), - \( T \) is the tension in the string (60.5 N), - \( \mu \) is the linear mass density of the string. First, solve for \( \mu \): \[ \mu = \frac{T}{v^2} \] Calculate \( \mu \) using the given values: \[ \mu = \frac{60.5}{(43.2)^2} \] Then, calculate the mass (\( m \)) of the string using: \[ m = \mu \times L \] where \( L \) is the length of the string (16.5 m). This will give you the mass of the string, matching one of the provided options.
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