Translate the statement into a confidence interval. Approximate the level of confidence. In a survey of 1079 parents of children ages 8-14, 73% say they are willing to get a second or part-time job to pay for their children's college education and 43% say they lose sleep worrying about college costs. The survey's margin of error is +3%. Use the results from the survey about getting a second or part-time job. The confidence interval for the proportion is (0.700 0.760 (Round to three decimal places as needed.) Use the results from the survey about getting second or part-time job. The interval is a % confidence interval. (Round to one decimal place as needed.) Use the results from the survey about losing sleep. The confidence interval for the proportion is ( UD (Round to three decimal places as needed.) Use the results from the survey about losing sleep. The interval is a (Round to one decimal place as needed.) % confidence interval.

MATLAB: An Introduction with Applications
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Chapter1: Starting With Matlab
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Translate the statement into a confidence interval. Approximate the level of confidence.
In a survey of 1079 parents of children ages 8-14, 73% say they are willing to get a second or part-time job to pay for their children's college education and 43% say they lose sleep worrying about college
costs. The survey's margin of error is +3%.
Use the results from the survey about getting a second or part-time job.
The confidence interval for the proportion is (0.7000.760)
(Round to three decimal places as needed.)
Use the results from the survey about getting a second or part-time job.
The interval is a % confidence interval.
(Round to one decimal place as needed.)
Use the results from the survey about losing sleep.
The confidence interval for the proportion is
(Round to three decimal places as needed.)
Use the results from the survey about losing sleep.
The interval is a % confidence interval.
(Round to one decimal place as needed.)
Transcribed Image Text:Translate the statement into a confidence interval. Approximate the level of confidence. In a survey of 1079 parents of children ages 8-14, 73% say they are willing to get a second or part-time job to pay for their children's college education and 43% say they lose sleep worrying about college costs. The survey's margin of error is +3%. Use the results from the survey about getting a second or part-time job. The confidence interval for the proportion is (0.7000.760) (Round to three decimal places as needed.) Use the results from the survey about getting a second or part-time job. The interval is a % confidence interval. (Round to one decimal place as needed.) Use the results from the survey about losing sleep. The confidence interval for the proportion is (Round to three decimal places as needed.) Use the results from the survey about losing sleep. The interval is a % confidence interval. (Round to one decimal place as needed.)
The prices of a random sample of 23 new motorcycles have a sample standard deviation of $3726. Assume the sample is from a normally distributed population. Construct a confidence interval for the
population variance o and the population standard deviation o. Use a 99% level of confidence. Interpret the results.
What is the confidence interval for the population variance o2?
(I) (Round to the nearest integer as needed.)
Interpret the results. Select the correct choice below and fill in the answer box(es) to complete your choice.
(Round to the nearest integer as needed.)
O A. With 99% confidence, you can say that the population variance is less than
O B. With 99% confidence, you can say that the population variance is between
and
OC. With 1% confidence, you can say that the population variance is between
O D. With 1% confidence, you can say that the population variance is greater than
and
What is the confidence interval for the population standard deviation a?
!) (Round to the nearest integer as needed.)
Interpret the results. Select the correct choice below and fill in the answer box(es) to complete your choice.
(Round to the nearest integer as needed.)
O A. With 1% confidence, you can say that the population standard deviation is between $
and O B. With 1% confidence, you can say that the population standard deviation is less than $
O C. With 99% confidence, you can say that the population standard deviation is beaveen $
O D. With 99% confidence, you can say that the population standard deviation is greater than
Transcribed Image Text:The prices of a random sample of 23 new motorcycles have a sample standard deviation of $3726. Assume the sample is from a normally distributed population. Construct a confidence interval for the population variance o and the population standard deviation o. Use a 99% level of confidence. Interpret the results. What is the confidence interval for the population variance o2? (I) (Round to the nearest integer as needed.) Interpret the results. Select the correct choice below and fill in the answer box(es) to complete your choice. (Round to the nearest integer as needed.) O A. With 99% confidence, you can say that the population variance is less than O B. With 99% confidence, you can say that the population variance is between and OC. With 1% confidence, you can say that the population variance is between O D. With 1% confidence, you can say that the population variance is greater than and What is the confidence interval for the population standard deviation a? !) (Round to the nearest integer as needed.) Interpret the results. Select the correct choice below and fill in the answer box(es) to complete your choice. (Round to the nearest integer as needed.) O A. With 1% confidence, you can say that the population standard deviation is between $ and O B. With 1% confidence, you can say that the population standard deviation is less than $ O C. With 99% confidence, you can say that the population standard deviation is beaveen $ O D. With 99% confidence, you can say that the population standard deviation is greater than
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