Addr:CodeОх0007FFОх02240E1EOC250AОх04Ох06Ох0803F9Ox0AOE00Охос24C2ОхОЕ3C00 Translate the following segment of C program into assembly code for the machine givenyou may assume the integers a and b are already given in register RO and R1 respectively. Byconvention, put the returned value in R7.Note:while (a != b) {if (a > b) {a = a - b} else {b=b - a}}return a

Solution: Given code c code : while(a != b){ if(a > b){ a = a - b;…

Answered: Translate the following segment of C…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Write a C program that uses a function to calculate Rt. The user will be prompted to enter R1, R2 & R3 which will be passed to the function as parameters, do not use global variables or pointers. The values have no specified range for them but if any of the 3 inputs are less than 0, the function should return 0. The main function should then display the calculated value of Rt with 2 decimal places or an appropriate error message. (Do not use printf or scanf inside the function ... all input/output should be in main) Use appropriate message to prompt the user to enter each value. Three resistors (R1, R2 and R3) are connected so that R1 & R2 are in parallel then in series with R3. Their equivalent resistance (Rt) is calculated using the following equation: Rt=(R1xR2/R1+R2)+R3
23. Write a C++ program that reads a positive integer n and then prints the following pattern which has got 2n-1 rows of stars. The following pattern shows the required output for the case n = 6. Your cout statement must print only one digit at a time. Therefore you must use a nested loop. You can choose whichever loop structure (for, while, do-while or combination of them) to use. The following diagram shows the answer for n = 6. 1 1 1 1 1 1 1 2 2 3 2 3 4 2 3 4 5 2 3 4 5 2 3 4 5 1 1 2 3 1 2 1 2 3 4 5 6 5 5 1 2 1 3 2 1 4 3 2 1 4 3 2 1 4 3 2 1 4 3 2 1 4 3 2 1 3 2 1 2 1 1
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In C++
Implement a subprogram which takes 4 numbers in the argument registers $a0...$a3, andreturns the largest value and the average in $v0 and $v1 to the calling program. Theprogram must be structured as follows:Subprogram largestAndAverage($a1, $a2, $a3, $a4){ int var0 = $a0, var1 = $a1, var2 = $a2, var3 = $a3; $s0 = getLarger($a1, $a2); $s0 = getLarger($s0, $a3); $v0 = getLarager(s0, $a4); // Largest is in $v0 $v1 = (var0 + var1 + var2 + var3)/ 4; // Aversge is in $v1 return;}Subprogram getLarger($a0, $a1) { $v0 = $a0 if ($a1 > $a0) $v0 = $a1 return;}Take note of how var0...var3 are used. The values of $a0 and $a1 (at least) must be placed on the stack because they are not immediately available when needed to calculate the average because they are modified during the call to getLarger. You must use the getLarger subprogram displayed above to calculate the greatest value for this problem, and it must be called before the average calculation. This indicates that at the very least $a0…

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Translate the following segment of C program into assembly code for the machine given you may assume the integers a and b are already given in register RO and R1 respectively. By convention, put the returned value in R7. Note: while (a != b) { if (a > b) { a = a - b } else { b=b - a } } return a