Translate the equation below into standard form using completing the square. Then identify the center and raidus of the circle. đâ+8x + y2 -10y – 23 – 0 A. (x+4)² + (y-5)² = 64 (x+4)² + (-5)² =. = 41 center (4,-5) and radius is 64 center (4, -5) and radius is √√41 (x+4)² + (-5) = 23 191 20.0 center (4, -5) and radius is √23 center (-4, 5) and radius is 8 B. D. (x+4)² + (y-5)² = 64

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
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### Problem 17
**Objective:** Translate the given equation into standard form using the method of completing the square. Then, identify the center and radius of the circle.

**Given Equation:**
\[ x^2 + 8x + y^2 - 10y - 23 = 0 \]

**Choices:**

**A.** 
\[ (x + 4)^2 + (y - 5)^2 = 64 \]
- Center: \((4, -5)\)
- Radius: \(64\)

**B.**
\[ (x + 4)^2 + (y - 5)^2 = 23 \]
- Center: \((4, -5)\)
- Radius: \(\sqrt{23}\)

**C.**
\[ (x + 4)^2 + (y - 5)^2 = 41 \]
- Center: \((4, -5)\)
- Radius: \(\sqrt{41}\)

**D.**
\[ (x + 4)^2 + (y - 5)^2 = 64 \]
- Center: \((-4, 5)\)
- Radius: \(8\)

The correct choice has been marked as:

**Correct Answer:**
**C.** 
\[ (x + 4)^2 + (y - 5)^2 = 41 \]
- Center: \((4, -5)\)
- Radius: \(\sqrt{41}\)
Transcribed Image Text:### Problem 17 **Objective:** Translate the given equation into standard form using the method of completing the square. Then, identify the center and radius of the circle. **Given Equation:** \[ x^2 + 8x + y^2 - 10y - 23 = 0 \] **Choices:** **A.** \[ (x + 4)^2 + (y - 5)^2 = 64 \] - Center: \((4, -5)\) - Radius: \(64\) **B.** \[ (x + 4)^2 + (y - 5)^2 = 23 \] - Center: \((4, -5)\) - Radius: \(\sqrt{23}\) **C.** \[ (x + 4)^2 + (y - 5)^2 = 41 \] - Center: \((4, -5)\) - Radius: \(\sqrt{41}\) **D.** \[ (x + 4)^2 + (y - 5)^2 = 64 \] - Center: \((-4, 5)\) - Radius: \(8\) The correct choice has been marked as: **Correct Answer:** **C.** \[ (x + 4)^2 + (y - 5)^2 = 41 \] - Center: \((4, -5)\) - Radius: \(\sqrt{41}\)
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