Transient analysis: 1) Use Thevenin's theorem to convert the circuit of Figure 1 to the circuit of Figure 2 by finding out the values of V1 and R1. Now using the circuit of Figure 2, find out the expression of i c(t) as a function of time. Figure 1: 1 k? 1.25 k? t=0 18 V 3 k 2 mA 1 F Figure 2: R =? k? t=0 Vị =? V -1 µF vi(t) 2) Now we want to check if the superposition principle works in this case or not. First we tum the voltage source off and keep the current source on in the following Figure 1. Then we convert it to the circuit of Figure 2 using Thevenin's theorem. Now using the circuit of Figure 2, find out the expression of ic_1(t) as a function of time. Figure 1: 1 k? 1.25 k t=0 )ov 3 k 2 mA 1 F
Transient analysis: 1) Use Thevenin's theorem to convert the circuit of Figure 1 to the circuit of Figure 2 by finding out the values of V1 and R1. Now using the circuit of Figure 2, find out the expression of i c(t) as a function of time. Figure 1: 1 k? 1.25 k? t=0 18 V 3 k 2 mA 1 F Figure 2: R =? k? t=0 Vị =? V -1 µF vi(t) 2) Now we want to check if the superposition principle works in this case or not. First we tum the voltage source off and keep the current source on in the following Figure 1. Then we convert it to the circuit of Figure 2 using Thevenin's theorem. Now using the circuit of Figure 2, find out the expression of ic_1(t) as a function of time. Figure 1: 1 k? 1.25 k t=0 )ov 3 k 2 mA 1 F
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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I know you cany solve all due to the rules of chegg,But the question is interrelated,Kindly solve all
![Transient analysis:
1) Use Thevenin's theorem to convert the circuit of Figure 1 to the circuit of Figure 2 by
finding out the values of V1 and R1. Now using the circuit of Figure 2, find out the
expression of i_c(t) as a function of time.
Figure 1:
1 k?
1.25 kf?
t=0
8 V
3 kf?
2 mA(
1 F
i(t)
Figure 2:
R =? k?
t= 0
V =? V+
tielt)
2) Now we want to check if the superposition principle works in this case or not. First we
turn the voltage source off and keep the current source on in the following Figure 1.
Then we convert it to the circuit of Figure 2 using Thevenin's theorem. Now using the
circuit of Figure 2, find out the expression of ic_1(t) as a function of time.
Figure 1:
1 k?
1.25 kf?
t = 0
OV
3 k.
2 mA (!
1 uF](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffa1fda29-7745-40f2-b085-dfaa13cf009e%2F5e4932f9-f71f-4fff-bd56-585d6d79b905%2Fov15c4_processed.png&w=3840&q=75)
Transcribed Image Text:Transient analysis:
1) Use Thevenin's theorem to convert the circuit of Figure 1 to the circuit of Figure 2 by
finding out the values of V1 and R1. Now using the circuit of Figure 2, find out the
expression of i_c(t) as a function of time.
Figure 1:
1 k?
1.25 kf?
t=0
8 V
3 kf?
2 mA(
1 F
i(t)
Figure 2:
R =? k?
t= 0
V =? V+
tielt)
2) Now we want to check if the superposition principle works in this case or not. First we
turn the voltage source off and keep the current source on in the following Figure 1.
Then we convert it to the circuit of Figure 2 using Thevenin's theorem. Now using the
circuit of Figure 2, find out the expression of ic_1(t) as a function of time.
Figure 1:
1 k?
1.25 kf?
t = 0
OV
3 k.
2 mA (!
1 uF
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