Transform: F (s) 18-16 s²-08-13 Of(t) = 4e 3 sin2t – 4e-3t 31 cos2t O f(t) = 4e³t cos2t 4c sin2t O f(t) = 4e 3¹ cos2t 4e-3 sin2t O f(t) = 4e³ sin2t4e³ cos2t

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transform:
F (s) = 16
3²-08-13
O f(t) = 4e-3 sin2t -4e-cos2t
O f(t) = 4e cos2t - 4c" sin2t
Of(t)-4e-³¹ cos21 - 4e-sin21
O f(t) = 4e sin2t 4e cos2t
f(t) = 4c
4e-³¹ sin2t 2c¯¾cos2t
Of(t) = 4e sin2t - 2ecos2t
© f(t) — 4e-3 cos2t
2c 30
Of(t) = 4e" cos2t
2e" sin2t
Transcribed Image Text:Transform: F (s) = 16 3²-08-13 O f(t) = 4e-3 sin2t -4e-cos2t O f(t) = 4e cos2t - 4c" sin2t Of(t)-4e-³¹ cos21 - 4e-sin21 O f(t) = 4e sin2t 4e cos2t f(t) = 4c 4e-³¹ sin2t 2c¯¾cos2t Of(t) = 4e sin2t - 2ecos2t © f(t) — 4e-3 cos2t 2c 30 Of(t) = 4e" cos2t 2e" sin2t
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