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Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
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TRANSCRIBE THE FOLLOWING TEXT IN DIGITAL FORMAT
![A
Equation of the
i.e.
Y
-K/2₂0) 0
For
نه ابدارید
(0₂-1/3)
K > O
12
meter
Case
By given
K
line is
oroの
y
K
-K
7+
The para
but in
any
the line with Coordinate axes
3
= 1
2x + 3y + K = 0
18
B
O
So, value of K is
For
may be positive
negative
the triangle OAB formed by
night angle
is a
triangle whose bose length is 1-2/2 | and hightat 1/3 |
is
So, the area of the triangle is 2/2 1-2/2 1·1-15/3/1
Surface units.
·
i.e.
42
Condition we must have
1
(0₂-1/3)
K is ± 6√6
12
or, K² = 12 X 18 = 2³.33
K = ± 6√6
(-K/2₂₂0)
A
K <O
on
X](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc094a8e4-aa9c-4bd1-817e-d5e48fc50cde%2F68cc8eb3-b6fc-49b0-86c0-9e477043aa84%2Fglnc2je_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A
Equation of the
i.e.
Y
-K/2₂0) 0
For
نه ابدارید
(0₂-1/3)
K > O
12
meter
Case
By given
K
line is
oroの
y
K
-K
7+
The para
but in
any
the line with Coordinate axes
3
= 1
2x + 3y + K = 0
18
B
O
So, value of K is
For
may be positive
negative
the triangle OAB formed by
night angle
is a
triangle whose bose length is 1-2/2 | and hightat 1/3 |
is
So, the area of the triangle is 2/2 1-2/2 1·1-15/3/1
Surface units.
·
i.e.
42
Condition we must have
1
(0₂-1/3)
K is ± 6√6
12
or, K² = 12 X 18 = 2³.33
K = ± 6√6
(-K/2₂₂0)
A
K <O
on
X
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