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Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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TRANSCRIBE THE FOLLOWING TEXT IN DIGITAL FORMAT
![27.
we
міх, у)
position vector
in R².
have
1 μ =
Tr
=
√x² + y²
तारे
to Show
7(4²) = 24
1
" =
is
Now, if f(x,y) be
у
the
x i + y j
that
when (x, y) + (0,0)
length of
for each point (x,y)
and
of(x,y) = (i3/2 + $ 24 ) f(x,y)
тых, у
id
fixe
х,у)
әх
бу
the
a function of R²,
of R², then
First
TM=
ㅋ
we
Fr
since, r(x,y)=√x² + y²
és Jr =
Tr=
Hence
show
1 r
μ
Now,
H
( iz + j) n = [ ² 2 + j 2 ) √x ² + y ²
i z
ау
dæ
- (22//W) + 12 (²)
i s
=/i
туя
dx
бу
=/ix
= [ix + √2² +4²
X_1
=
=(²
that
i x
1
√x² + y²
1 r
we
√x² + y²
روندان
the proof.
=
(x² + y j)
x 2x + jx 1
Ir
+ in the stre)
j y
+ y
show that
2 Jetty: x*y) ; (x₁y) + (09)
{ x=
; (x, y) = (0,0)
; (x, y) = (0,0)
• • r = √x²³² + y²
μ = x² + y j
xi
and (x, y) = (0,0)
Since,
→
介
r = √√x ²² + y²
=> μ²³ = (√x² + y²
(√x² + y²) ²
⇒ x² = x² + y²
☺☺.
موہو لا
رمندان
ů
= (₁²) = (iz + $ $ ) x² = ( i 2/2 + 1 + ) (x ² + y ² )
is
j
ter
d
j
dy
dy
⇒ O (re?).
=
روہواں
7[r²) = (i (2x) + j(ay
z x i + 2 Y j
obe ²) = 2(x²+ y j)
(1
11
i 2 ( x ³² + y ² ) + j } (x² + y ² )
2
dxc
бу
= 2 μ
Hence, the proof
poo
x² + y²
11
=
A
r = x² + y j }
xi
ہو
2(xity ý)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F05acc741-d43b-42c1-835f-678a6d9974b9%2F5fa66f9c-eb7c-4fbb-a9d1-485e904b8b06%2Fx7vp4h4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:27.
we
міх, у)
position vector
in R².
have
1 μ =
Tr
=
√x² + y²
तारे
to Show
7(4²) = 24
1
" =
is
Now, if f(x,y) be
у
the
x i + y j
that
when (x, y) + (0,0)
length of
for each point (x,y)
and
of(x,y) = (i3/2 + $ 24 ) f(x,y)
тых, у
id
fixe
х,у)
әх
бу
the
a function of R²,
of R², then
First
TM=
ㅋ
we
Fr
since, r(x,y)=√x² + y²
és Jr =
Tr=
Hence
show
1 r
μ
Now,
H
( iz + j) n = [ ² 2 + j 2 ) √x ² + y ²
i z
ау
dæ
- (22//W) + 12 (²)
i s
=/i
туя
dx
бу
=/ix
= [ix + √2² +4²
X_1
=
=(²
that
i x
1
√x² + y²
1 r
we
√x² + y²
روندان
the proof.
=
(x² + y j)
x 2x + jx 1
Ir
+ in the stre)
j y
+ y
show that
2 Jetty: x*y) ; (x₁y) + (09)
{ x=
; (x, y) = (0,0)
; (x, y) = (0,0)
• • r = √x²³² + y²
μ = x² + y j
xi
and (x, y) = (0,0)
Since,
→
介
r = √√x ²² + y²
=> μ²³ = (√x² + y²
(√x² + y²) ²
⇒ x² = x² + y²
☺☺.
موہو لا
رمندان
ů
= (₁²) = (iz + $ $ ) x² = ( i 2/2 + 1 + ) (x ² + y ² )
is
j
ter
d
j
dy
dy
⇒ O (re?).
=
روہواں
7[r²) = (i (2x) + j(ay
z x i + 2 Y j
obe ²) = 2(x²+ y j)
(1
11
i 2 ( x ³² + y ² ) + j } (x² + y ² )
2
dxc
бу
= 2 μ
Hence, the proof
poo
x² + y²
11
=
A
r = x² + y j }
xi
ہو
2(xity ý)
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