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TRANSCRIBE THE FOLLOWING TEXT IN DIGITAL FORMAT

TRANSCRIBE THE FOLLOWING TEXT IN DIGITAL FORMAT

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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TRANSCRIBE THE FOLLOWING TEXT IN DIGITAL FORMAT

 

So line currents IR = √3 | Jph | = 72.015 Amp L-36 Reactive Sey = √5 $ phl = 42.05/-156.86 Amp 1/83. 14 Amp IB (P) Real (or) ture w complex power power P power 72.05 = * = √3 V₂ IL cosø = √3 x 208 x 72.05 cos (36.86) 20768.455 watts. N = √3 Y₂ IL Sinds (@= 25957. 20622 x0.6 15574.32 (20768.455 -36.86* cost= Cost = Var [+] ₁ + 15574.32 power factor of Load cose - 20768-455 √3 VL IL 20768-45 0.8 1.32) 25957.20 Lag NA = (P+ja)
Transcribed Image Text:So line currents IR = √3 | Jph | = 72.015 Amp L-36 Reactive Sey = √5 $ phl = 42.05/-156.86 Amp 1/83. 14 Amp IB (P) Real (or) ture w complex power power P power 72.05 = * = √3 V₂ IL cosø = √3 x 208 x 72.05 cos (36.86) 20768.455 watts. N = √3 Y₂ IL Sinds (@= 25957. 20622 x0.6 15574.32 (20768.455 -36.86* cost= Cost = Var [+] ₁ + 15574.32 power factor of Load cose - 20768-455 √3 VL IL 20768-45 0.8 1.32) 25957.20 Lag NA = (P+ja)
1 208 V L impedance in TFB are delta 'Iph phase (RY) line Similarly B Since in TER Same V₂ current 4+j3 = 208 4+√3 in = R Iph (YB) Vph Iph (BR) 4+j³ connected system V₂ = voltage voltage = phase voltage. delta annected Z₁, Z₂, Z3 = Y Vph Lon 20% L00 Loe Zph 5/36-86 11.6 L-36-860 VL = Vph. 208 L-120 5 L36.96 241- = systém 4 +j3. = - A connection |1₂| = √3 Iph (fx = 1y = 18) FR ·156.86 208 4+120 5/36.86 = 5 /36.86° 0 Amp Amp 41.6 L + 83.1 Астр
Transcribed Image Text:1 208 V L impedance in TFB are delta 'Iph phase (RY) line Similarly B Since in TER Same V₂ current 4+j3 = 208 4+√3 in = R Iph (YB) Vph Iph (BR) 4+j³ connected system V₂ = voltage voltage = phase voltage. delta annected Z₁, Z₂, Z3 = Y Vph Lon 20% L00 Loe Zph 5/36-86 11.6 L-36-860 VL = Vph. 208 L-120 5 L36.96 241- = systém 4 +j3. = - A connection |1₂| = √3 Iph (fx = 1y = 18) FR ·156.86 208 4+120 5/36.86 = 5 /36.86° 0 Amp Amp 41.6 L + 83.1 Астр
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