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TRANSCRIBE THE FOLLOWING TEXT IN DIGITAL FORMAT

TRANSCRIBE THE FOLLOWING TEXT IN DIGITAL FORMAT

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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TRANSCRIBE THE FOLLOWING TEXT IN DIGITAL FORMAT

(8) Current through the load Power ab Lorbed S = S Power factor of = 4₁₂ = £₂-fR by load load * 10 Lo- 4L35 7-104 L-18-84 Avg power delivered to load Apparent power delivered or A supplied by VL CL 80L35 x (7-1042-18-84 ) * 80 L35 x 7-104 L18.84 568-32 [53-84 VA = = 335 32 to load Power factor = Coso P-f= = Source to load Cos 53.84 0.59 568-32 L53-89 335 32 +458-86 1 = 568.32 VA
Transcribed Image Text:(8) Current through the load Power ab Lorbed S = S Power factor of = 4₁₂ = £₂-fR by load load * 10 Lo- 4L35 7-104 L-18-84 Avg power delivered to load Apparent power delivered or A supplied by VL CL 80L35 x (7-1042-18-84 ) * 80 L35 x 7-104 L18.84 568-32 [53-84 VA = = 335 32 to load Power factor = Coso P-f= = Source to load Cos 53.84 0.59 568-32 L53-89 335 32 +458-86 1 = 568.32 VA
Given (d) C = 4 L35 have that We Power supplied by each € each component To find above parameter we 202 which Power to calculate or absorb V the resistor to (a) Power Supplied by source Circuit 5 = / the £x 20 * S= V₁₂ £5² 800 (35 (a) Avg power supplied by source (d) Apparent power supplied by source (b) 10 Lo Power supplied to load Amp 4L35 x 20 the will first find the voltage acralt is given by 202 resistor PR = 111² R 90 L30 x (1010) = 2012 * 80 L35 Lood 80 L35 v 655.32 +458.86 i 655.32 W = 800 VA PR= 320 W (es. Apparent power across the 2012 resistor will also be 320 VA the resistance has a unit power factor because S = 320 VA 4²x 20 = 800 L35 VA 320 W To find power supplied to load we will find the current flowing across load I voltage across it. VL = VR As they are in parallel }
Transcribed Image Text:Given (d) C = 4 L35 have that We Power supplied by each € each component To find above parameter we 202 which Power to calculate or absorb V the resistor to (a) Power Supplied by source Circuit 5 = / the £x 20 * S= V₁₂ £5² 800 (35 (a) Avg power supplied by source (d) Apparent power supplied by source (b) 10 Lo Power supplied to load Amp 4L35 x 20 the will first find the voltage acralt is given by 202 resistor PR = 111² R 90 L30 x (1010) = 2012 * 80 L35 Lood 80 L35 v 655.32 +458.86 i 655.32 W = 800 VA PR= 320 W (es. Apparent power across the 2012 resistor will also be 320 VA the resistance has a unit power factor because S = 320 VA 4²x 20 = 800 L35 VA 320 W To find power supplied to load we will find the current flowing across load I voltage across it. VL = VR As they are in parallel }
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