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TRANSCRIBE THE FOLLOWING SOLUTION IN DIGITAL FORMAT PLEASE

TRANSCRIBE THE FOLLOWING SOLUTION IN DIGITAL FORMAT PLEASE

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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TRANSCRIBE THE FOLLOWING SOLUTION IN DIGITAL FORMAT PLEASE

0.5+60 10.5 = 2.857 ft/sec force balonce on the block +bullet (m+mb) d²c dt2 =-1²x let the solution be xlt) = A sinut (m+mb) (-Aw² Sinot) = -K A sinut w=√ K = √ 100+32 +121l bf/ft m+mb 10.5lb W= 60.475²1 x= A sin (60.474) ft v(t) = dx (t) dt The = 60.47 A cos (60.47 +) ft/sec v (0) = -√ = -2.857 60.47xA==2.857 A=-0.04725 resulting position of block is selt) = -0.04725 Sin (60.477) ft The resulting Velocity is V(t) = -2.857 Cos (60.477) ft/sec
Transcribed Image Text:0.5+60 10.5 = 2.857 ft/sec force balonce on the block +bullet (m+mb) d²c dt2 =-1²x let the solution be xlt) = A sinut (m+mb) (-Aw² Sinot) = -K A sinut w=√ K = √ 100+32 +121l bf/ft m+mb 10.5lb W= 60.475²1 x= A sin (60.474) ft v(t) = dx (t) dt The = 60.47 A cos (60.47 +) ft/sec v (0) = -√ = -2.857 60.47xA==2.857 A=-0.04725 resulting position of block is selt) = -0.04725 Sin (60.477) ft The resulting Velocity is V(t) = -2.857 Cos (60.477) ft/sec
Mass of block m=1016 K=1001b/m =100xglbp/inch mass of bullet velocity of bullet Mb=0-516 Vb=60ft/sec By Seeing the diagram We solution mmmm K Assume ру m Goft/sec g=32 ft/s² Applying conservation of and x before momentum after the bullet hits the block mxmbv = myo +mb+b V v= mbv m+mb find the
Transcribed Image Text:Mass of block m=1016 K=1001b/m =100xglbp/inch mass of bullet velocity of bullet Mb=0-516 Vb=60ft/sec By Seeing the diagram We solution mmmm K Assume ру m Goft/sec g=32 ft/s² Applying conservation of and x before momentum after the bullet hits the block mxmbv = myo +mb+b V v= mbv m+mb find the
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