Transcribe in digital format the following text
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
Transcribe in digital format the following text
![NOW, (P₁-1) + (P₂-1) = P₁ + R₂-2 = P-2
(P₁−1)²+(1₂-1)² + 2 (P-1) (P₂-1)
= (P-2)² [Squaring bort
sides]
→ (P₁-1) ² + (₁₂-1) ² ≤ (P-2) ² [22 (1₁-1) (12-1) > 0]
→ P₁² + P₂² - 2 (P₁+P₂) + 2 ≤ p²-4P+4
=
= P₁² + P₂² ≤ p²-2p+2
So, the maximus no.
[²² P₁+₁₂=P]
of edges in G
= ²/²/2 [ P₁² + P₂²² -P] ≤
But, given that,
p²3p+2
2
2
(P-1) (P-2)
2
G has more than (P-1) (P-2) edges.
15ms,
We get a contradiction.
so, our assumption is wrong.
Hence,
G is connected (Prove)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F526a6d9d-32b7-4f2d-90af-ff9540132ca2%2F84961ec9-3b47-41d6-a7d5-23cac7fc3232%2Ffm1p58f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:NOW, (P₁-1) + (P₂-1) = P₁ + R₂-2 = P-2
(P₁−1)²+(1₂-1)² + 2 (P-1) (P₂-1)
= (P-2)² [Squaring bort
sides]
→ (P₁-1) ² + (₁₂-1) ² ≤ (P-2) ² [22 (1₁-1) (12-1) > 0]
→ P₁² + P₂² - 2 (P₁+P₂) + 2 ≤ p²-4P+4
=
= P₁² + P₂² ≤ p²-2p+2
So, the maximus no.
[²² P₁+₁₂=P]
of edges in G
= ²/²/2 [ P₁² + P₂²² -P] ≤
But, given that,
p²3p+2
2
2
(P-1) (P-2)
2
G has more than (P-1) (P-2) edges.
15ms,
We get a contradiction.
so, our assumption is wrong.
Hence,
G is connected (Prove)
![9
Given that, G is a graph of Orden p and his size
greaten than (P-1)
(P-1) (P-2)
=
2
2
we have to show,
Then
The result is true orily when
G is Simple graph
Now, Let us assume that G is not connected.
G has at least two Connected Components.
Say G₁ G₂
9
Suppose,
then,
P+P₂=P
as the graph is simple,
and
The maximum
Then
G is connected.
The Order of the
Рід P2
graph G₁9 G₂ are P₁ 3 Pz
respectively
so both G₁ 9. G₂ are Simple.
of edges in Gi is
PiCz
Pi (Pi-1)
2
+
no of edges
=
so, the maximum sio. of edges in G
P₁ (P₁-1)
P2 (P₂-1).
2
2
; 1=1,2
= = [₁²³+R² = (₁+B₂)] = { [9²6²³=P]
-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F526a6d9d-32b7-4f2d-90af-ff9540132ca2%2F84961ec9-3b47-41d6-a7d5-23cac7fc3232%2Fw1txwm4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:9
Given that, G is a graph of Orden p and his size
greaten than (P-1)
(P-1) (P-2)
=
2
2
we have to show,
Then
The result is true orily when
G is Simple graph
Now, Let us assume that G is not connected.
G has at least two Connected Components.
Say G₁ G₂
9
Suppose,
then,
P+P₂=P
as the graph is simple,
and
The maximum
Then
G is connected.
The Order of the
Рід P2
graph G₁9 G₂ are P₁ 3 Pz
respectively
so both G₁ 9. G₂ are Simple.
of edges in Gi is
PiCz
Pi (Pi-1)
2
+
no of edges
=
so, the maximum sio. of edges in G
P₁ (P₁-1)
P2 (P₂-1).
2
2
; 1=1,2
= = [₁²³+R² = (₁+B₂)] = { [9²6²³=P]
-
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