Train A is traveling at a constant speed VÀ = 37 mi/hr while car B travels in a straight line along the road as shown at a constant speed VB. A conductor C in the train begins to walk to the rear of the train car at a constant speed of 6 ft/sec relative to the train. If the conductor perceives car B to move directly westward at 19 ft/sec, how fast is the car traveling? UB -1x
Train A is traveling at a constant speed VÀ = 37 mi/hr while car B travels in a straight line along the road as shown at a constant speed VB. A conductor C in the train begins to walk to the rear of the train car at a constant speed of 6 ft/sec relative to the train. If the conductor perceives car B to move directly westward at 19 ft/sec, how fast is the car traveling? UB -1x
Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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![### Relative Motion of Train and Car
**Problem Statement:**
Train A is traveling at a constant speed \( v_A = 37 \) mi/hr while car B travels in a straight line along the road as shown at a constant speed \( v_B \). A conductor C in the train begins to walk to the rear of the train car at a constant speed of 6 ft/sec relative to the train. If the conductor perceives car B to move directly westward at 19 ft/sec, how fast is the car traveling?
**Diagram Explanation:**
The diagram shows:
1. Train A moving on a track at a speed \( v_A = 37 \) mi/hr.
2. Conductor C is walking to the rear of the train at a speed of 6 ft/sec (relative to the train).
3. Car B is traveling at speed \( v_B \) on a road parallel to the train.
4. Coordinate axes \( x \) (eastward) and \( y \) (northward) along with an angle \( \theta \) showing the path direction of car B relative to the train.
**Given Data:**
- Speed of Train \( v_A = 37 \) mi/hr
- Speed of Conductor = 6 ft/sec (relative to the train)
- Perceived Speed of Car by Conductor = 19 ft/sec toward west
**Conversion Factor:**
- To convert speeds from ft/sec to mi/hr, we use the conversion factor: \(1 \) ft/sec = \( 0.681818 \) mi/hr.
**Solution:**
To solve the problem, the perceived motion must be converted to common units and analyzed using relative velocity principles. The details of the calculation involve:
1. Convert the conductor's speed to mi/hr:
\[ 6 \, \text{ft/sec} \times 0.681818 \, (\text{mi/hr per ft/sec}) = 4.09 \, \text{mi/hr} \]
2. Given that the perceived westward speed of the car is 19 ft/sec (relative to the conductor):
\[ 19 \, \text{ft/sec} \times 0.681818 \, (\text{mi/hr per ft/sec}) = 12.95 \, \text{mi/hr} \]
3. The relative speed of the car, when perceived by the conductor moving at 4.09 mi/hr, points](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe33107d8-7e4c-42e3-bde6-e02cc2392684%2F4afa8eec-5bf0-40b7-a774-7ec426f135d8%2Fpn3agv_processed.png&w=3840&q=75)
Transcribed Image Text:### Relative Motion of Train and Car
**Problem Statement:**
Train A is traveling at a constant speed \( v_A = 37 \) mi/hr while car B travels in a straight line along the road as shown at a constant speed \( v_B \). A conductor C in the train begins to walk to the rear of the train car at a constant speed of 6 ft/sec relative to the train. If the conductor perceives car B to move directly westward at 19 ft/sec, how fast is the car traveling?
**Diagram Explanation:**
The diagram shows:
1. Train A moving on a track at a speed \( v_A = 37 \) mi/hr.
2. Conductor C is walking to the rear of the train at a speed of 6 ft/sec (relative to the train).
3. Car B is traveling at speed \( v_B \) on a road parallel to the train.
4. Coordinate axes \( x \) (eastward) and \( y \) (northward) along with an angle \( \theta \) showing the path direction of car B relative to the train.
**Given Data:**
- Speed of Train \( v_A = 37 \) mi/hr
- Speed of Conductor = 6 ft/sec (relative to the train)
- Perceived Speed of Car by Conductor = 19 ft/sec toward west
**Conversion Factor:**
- To convert speeds from ft/sec to mi/hr, we use the conversion factor: \(1 \) ft/sec = \( 0.681818 \) mi/hr.
**Solution:**
To solve the problem, the perceived motion must be converted to common units and analyzed using relative velocity principles. The details of the calculation involve:
1. Convert the conductor's speed to mi/hr:
\[ 6 \, \text{ft/sec} \times 0.681818 \, (\text{mi/hr per ft/sec}) = 4.09 \, \text{mi/hr} \]
2. Given that the perceived westward speed of the car is 19 ft/sec (relative to the conductor):
\[ 19 \, \text{ft/sec} \times 0.681818 \, (\text{mi/hr per ft/sec}) = 12.95 \, \text{mi/hr} \]
3. The relative speed of the car, when perceived by the conductor moving at 4.09 mi/hr, points
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