Toxic Cr(VI) can be precipitated from an aqueous solution by bubbling SO2 through the solution. How much SO2 is required to treat 3.00 x 108 L of 5.00x102 mM Cr(VI)? 2Cro +3s0, + 4H* Cr,(SO4)3+2H,0 kg

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Toxic Cr(VI) can be precipitated from an aqueous solution by bubbling SO2 through the solution. How much SO2 is required to treat 3.00 × 108 L of 5.00×10-2 mM Cr(VI)?

### Transcription for Educational Content

**Topic:** Precipitation of Toxic Cr(VI)

Toxic Cr(VI) can be precipitated from an aqueous solution by bubbling SO₂ through the solution. How much SO₂ is required to treat 3.00 x 10⁸ L of 5.00 x 10⁻² mM Cr(VI)?

**Chemical Reaction:**

\[ 
2 \text{CrO}_4^{2-} + 3 \text{SO}_2 + 4 \text{H}^+ \rightarrow \text{Cr}_2(\text{SO}_4)_3 + 2 \text{H}_2\text{O} 
\] 

**Calculation Box:**

\[ 
\boxed{\phantom{text}} \text{ kg} 
\]

### Explanation:

The provided equation describes the chemical reaction where chromate ions (\(\text{CrO}_4^{2-}\)) react with sulfur dioxide (SO₂) in the presence of hydrogen ions (\(\text{H}^+\)) to form chromium(III) sulfate (\(\text{Cr}_2(\text{SO}_4)_3\)) and water (\(\text{H}_2\text{O}\)). 

To determine the amount of SO₂ needed in kilograms, one must consider the volume and concentration of the Cr(VI) solution, then apply stoichiometry based on the given balanced chemical equation.
Transcribed Image Text:### Transcription for Educational Content **Topic:** Precipitation of Toxic Cr(VI) Toxic Cr(VI) can be precipitated from an aqueous solution by bubbling SO₂ through the solution. How much SO₂ is required to treat 3.00 x 10⁸ L of 5.00 x 10⁻² mM Cr(VI)? **Chemical Reaction:** \[ 2 \text{CrO}_4^{2-} + 3 \text{SO}_2 + 4 \text{H}^+ \rightarrow \text{Cr}_2(\text{SO}_4)_3 + 2 \text{H}_2\text{O} \] **Calculation Box:** \[ \boxed{\phantom{text}} \text{ kg} \] ### Explanation: The provided equation describes the chemical reaction where chromate ions (\(\text{CrO}_4^{2-}\)) react with sulfur dioxide (SO₂) in the presence of hydrogen ions (\(\text{H}^+\)) to form chromium(III) sulfate (\(\text{Cr}_2(\text{SO}_4)_3\)) and water (\(\text{H}_2\text{O}\)). To determine the amount of SO₂ needed in kilograms, one must consider the volume and concentration of the Cr(VI) solution, then apply stoichiometry based on the given balanced chemical equation.
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