Total Grades Both Sexes Female Male No. Kindergarten 75,384 37,183 38,201 Basic education First episode 210,269 103,636 106,633 Basic education Second episode 263,831 128,493 135,338 General Education 560 243 317 Grades (1-4) General Education 16,175 8,169 8,006 Grades (5-10) After Basic Education 84,232 41,142 43,090 Grades (11-12) Grades (1-6) 31.031 15,018 16,013 Grades (7-9) 11.796 5,629 6,167 Grades (10-12) 7.803 3,473 4,330 Total 701,081 342,986 358,095 1. Calculate the percentage of males and females in each category. 2. Calculate the distribution percentage of students in each category gender wise. 3. Make a bar chart for the distribution percentage of males in each category. 31

Total Grades Both Sexes Female Male No. Kindergarten 75,384 37,183 38,201 Basic education First episode 210,269 103,636 106,633 Basic education Second episode 263,831 128,493 135,338 General Education 560 243 317 Grades (1-4) General Education 16,175 8,169 8,006 Grades (5-10) After Basic Education 84,232 41,142 43,090 Grades (11-12) Grades (1-6) 31.031 15,018 16,013 Grades (7-9) 11.796 5,629 6,167 Grades (10-12) 7.803 3,473 4,330 Total 701,081 342,986 358,095 1. Calculate the percentage of males and females in each category. 2. Calculate the distribution percentage of students in each category gender wise. 3. Make a bar chart for the distribution percentage of males in each category. 31

Name: TotalGradesBoth SexesFemaleMaleNo.Kindergarten75,38437,18338,201Basic
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Description: TotalGradesBoth SexesFemaleMaleNo.Kindergarten75,38437,18338,201Basic educationFirst episode210,269103,636106,633Basic educationSecond episode263,831128,493135.338General Education560243317Grades (1-4)General Education16,1758,1698,006Grades (5-10)Af

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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question.Age (Years) Less than high school High school graduate Some college College Degreegraduate15 to 17 12,723 210 132 2918 to 34 9,655 19,231 25,444 17,49735 to 49 6,412 16,642 16,756 21,12550+ 13,693 34,110 26,461 29,899Figure 1 - 2013 U.S. population, in thousands, by age and educational attainment.Source: Census, U.S. Bureau of the CensusFind the probability that in the year 2013, a U.S. resident was a High school graduate. Writethe probability as a percent rounded to the nearest tenth.2
City Population "Fire/EMS spending per resident" "Fire/EMS personnel per 1000 residents" # of fire personnel Boston 608,352 $452.15 3.4 2068 San Francisco 799,183 $315.81 2.2 1758 Columbus, OH 747,755 $255.70 2.1 1570 Seattle 594,210 $247.75 1.8 1070 Baltimore 637,455 $225.98 2.7 1721 Memphis 674,028 $220.22 2.5 1685 Detroit 916,952 $201.54 1.6 1467 Nashville 590,807 $194.43 1.9 1123 Philadelphia 1,449,634 $187.63 1.6 2319 Jacksonville 805,605 $179.99 1.5 1208 New York 8,274,527 $157.56 1.7 14067 Los Angeles 3,834,340 $137.80 0.9 3451 calculate the average mean earnings of fire/ems personnel in each of the 12 cities.
How many wolves were there in 1980? *
9b In Africa in 2011, the number of deaths of a female from cardiovascular disease for different age groups are in the table below ("Global health observatory," 2013). In addition, the proportion of deaths of females from all causes for the same age groups are also in table below. Table: Deaths of Females for Different Age Groups Age 5-14 15-29 30-49 50-69 Total Cardiovascular Frequency 8 16 56 433 513 All Cause Proportion 0.10 0.12 0.26 0.52 Do the data show that the death from cardiovascular disease are in the same proportion as all deaths for the different age groups? Test at the 5% level. (iv) Are any of the expected frequency values (for which HO is true) for any cell in your table less than 5? Calculate the expected frequencies using technology, the select most correct answer: A. yes - this will not affect results of hypothesis test B. yes - this may invalidate results of hypothesis test C. no - this will not affect…
9a In Africa in 2011, the number of deaths of a female from cardiovascular disease for different age groups are in the table below ("Global health observatory," 2013). In addition, the proportion of deaths of females from all causes for the same age groups are also in table below. Table: Deaths of Females for Different Age Groups Age 5-14 15-29 30-49 50-69 Total Cardiovascular Frequency 8 16 56 433 513 All Cause Proportion 0.10 0.12 0.26 0.52 Do the data show that the death from cardiovascular disease are in the same proportion as all deaths for the different age groups? Test at the 5% level. (i) Which of the following statements correctly defines the null hypothesis HO? A. Deaths from cardiovascular disease in females are not in the same proportion as all deaths for the different age groups B. Deaths from cardiovascular disease in females are in the same proportion as all deaths for the different age groups C. neither of…
definition of population
Number oF Students Number oF Class boundary Kilograms 56- 59 52-55 48 - 51 44-47 4 40-43 3
Small Midsize Large Left Femur 1183 288 328 709 603 246 333 401 315 302 298 812 281 409 216 1643 740 881 936 883 470 Left Femur Right Femur 1263 325 445 1043 1477 1047 454 843 710 132 237 689 909 548 751 1206 775 552 672 555 291 Right Femur Small Midsize Large The accompanying data table lists results from car crash tests. Included in results from car crash tests are loads (pounds) on the left femur and right femur, and those values are shown in the table below. What characteristic of the data suggests that the appropriate method of analysis is two-way analysis of variance? That is, what is "two-way" about the data entered in the table? A. The load values are categorized using two different factors of femur (left or right) and size of car (small, midsize, or large). B. The data is measured in pounds, part of the imperial system, which is inherently two-way. C. There are two possiblities for the…
141% v Zoom Add Page Insert Table Chart Text Shape Media Comment Collaborate Format Document 13! 6227020800 14! 87178291200 This document has missing fonts. Show 15! 1307674368000 16! 20922789888000 17! 355687428096000 18! 6402373705728000 19! 121645100408832000 20! 2432902008176640000 2) After a recent bank robbery, three eyewitnesses reported seeing a man with glasses flee the scene. The police suspect Ricky and make up an identity parade of five men with glasses. Ricky takes his place in the parade alongside four randomly chosen stooges. Two of the eyewitnesses identify Ricky and the third points to one of the stooges. What's the probability that Ricky would have been chosen by two of the three eyewitnesses if each witness had chosen completely at random? Solve this problem using the Binomial Probability Mass Function. (Tip: This problem will be easier to solve if you first find p, the probability of success on any one trial; in other words, the probability of a single eyewitness…
Viewer age. Mobile/laptop. Tv screen. Row total 18-34 36 26 62 35-54 12 12 24 55+ 4 10 14 Total. 52. 48. 100 proability that a viewer is aged 18-34 (round your answer to 2 decimals places) proability that a viewer prefers watching videos on a tv screen (round your answer to 2 decimal places) percentage of viewers who 18-34 and prefer videos on a mobile or laptop device? Percentage of viewers? Percentage of viewers given they are 18-34 who prefer videos on a mobile or laptop device? percentage of viewers. Pecentage of viewers who are 35-54 or prefer videos on a mobile or laptop device? percentage of viewers.
Judy Holmes Textiles has decided to use a c-Chart to monitor the number of defects per pair of jeans produced by their manufacturing process. The c-Chart should be constructed with 3-sigma control limits. The operations manager randomly samples one pair of jeans at 10 successively selected time periods and counts the number of defects on the pair of jeans. Answer Table O In Control Control Chart Step 4 of 7: At the next time period, 23 defects were detected on the randomly selected pair of jeans. Determine if the process is "In Control" or "Out of Control". O Out of Control Copy Table Tables Keypad Keyboard Shortcuts Previous step answers Updated Control Chart
Number of ChildrenTable 1 shows the number of women (per 1000) between 15 and 50 years of age who have been married grouped by the number of children they have had. Table 2 gives the same information for women who have never been married.1 Number of Children Women per 1000 0 162 1 213 2 344 3 182 4 69 5+ 32 Table 1 Women who have been married Number of Children Women per 1000 0 752 1 117 2 72 3 35 4 15 5+ 10 Table 2 Women who have never been married 1http://www.census.gov/hhes/fertility/data/cps/2014.html, Table 1, June 2014. Condition gt requires numbers instead of "null" and "0" (a) Without doing any calculations, which of the two samples appears to have the highest mean number of children? Women who have been marriedWomen who have never been married Which of the distributions appears to have the mean most different from the median? Women who have been marriedWomen who have never been married…