Topics: Fundamentals of electrochemistry; Electrochemical cells Use general chemistry rules for significant figures. 1. A cell is constructed to reduce the Ag+ in AgCl(s) to Ag(s) at the cathode when current is passed through the cell. At the anode, Cu(s) is oxidized to Cu2+. If current of 0.500 A is passed through the cell for 101 minutes, calculate the mass of Cu(s) dissolved and mass of Ag(s) deposited. Half-cell reactions: Cathode: AgCl(s) + e ⇌ Ag(s) + Cl– Anode: Cu(s) ⇌ Ce2+ + 2e
Topics: Fundamentals of electrochemistry; Electrochemical cells Use general chemistry rules for significant figures. 1. A cell is constructed to reduce the Ag+ in AgCl(s) to Ag(s) at the cathode when current is passed through the cell. At the anode, Cu(s) is oxidized to Cu2+. If current of 0.500 A is passed through the cell for 101 minutes, calculate the mass of Cu(s) dissolved and mass of Ag(s) deposited. Half-cell reactions: Cathode: AgCl(s) + e ⇌ Ag(s) + Cl– Anode: Cu(s) ⇌ Ce2+ + 2e
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Topics: Fundamentals of
Use general chemistry rules for significant figures.
1. A cell is constructed to reduce the Ag+ in AgCl(s) to Ag(s) at the cathode when current is passed through the cell. At the anode, Cu(s) is oxidized to Cu2+.
If current of 0.500 A is passed through the cell for 101 minutes, calculate the mass of Cu(s) dissolved and mass of Ag(s) deposited. Half-cell reactions:
Cathode: AgCl(s) + e ⇌ Ag(s) + Cl–
Anode: Cu(s) ⇌ Ce2+ + 2e
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