Question in statistics:Topic regression:For 100 students of a class, theregression equation of marks in Statistics(X) on the marks in Commerce (Y) is 3Y5X + 180 = 0. The mean marks in%3DCommerce is 50 and variance of marks inStatistics is 4/9th of the variance of marksin Commerce. Find the mean marks inStatistics and the coefficient of correlationbetween marks in the two subjects.

Answered: Image /qna-images/answer/ea6ea28a-8d97-4691-bc46-927b3f0d3355.jpg

Answered: Topic regression: For 100 students of a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The table below gives the age and bone density for 5 women. Use the equation of the regression line, y= b0 + b1x, for predicting a women's bone density based on her age. The correlation coefficient may or may not be statically significant for the data given. Remember it wouldn't be appropiate to use regression line to make a prediction if the correlation coefficient isn;t statically significant. (y has a "hat" on the top) age 39 51 54 56 67 bone density 355 349 347 315 313 Find the estimated slope. Rund your answer to three decimal places. Find the estimated y-intercept. Round your answer to three decimal places. Determine the value of the dependent variable y at x+ 0 (y has a "hat" onthe top) Find the estimated value of y when x = 51. Round your answer to three decimal places. Substitute the values you found in steps 1 and 2 into the equation for the regression line to find the estimated linear model. According to this model, if the valueof the…
Ariel was running analyses over and over in census data and came across a correlation between weight and debt (r=.78). Independent variable is weight and dependent variable is debt. b) Curious Ariel noted some statistics on these weight (M=160lb, SD=15lb) and debt (M=196k, SD=20k). If Ariel wanted to calculate a regression equation, what would her slope and intercept be?
Describe the correlation coefficient and explain how it is used in regression analysis?
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An online retailer examined their transactional database to see how the value of total annual purchases ($) for individual customers was related to their annual income ($). They obtained the following regression model:Total annual purchases = -49.80 + 0.0246(annual income)correlation = 0.533(a) What does the slope tell us? (Annual Income/ Total Annual Purchases) is/are predicted to increase by ($0.0246 / -$49.80) for each additional $1 of (Annual Income/ Total Annual Purchases).(b) What does the intercept tell us? A.The intercept does not have a practical meaning in this context. B. Total annual purchases are predicted to be $0.0246 when annual income = 0. C. Total annual purchases are predicted to be $-49.80 when annual income = 0. D. Annual income is predicted to be $0.0246 when total annual purchases = 0. E. Annual income is predicted to be $-49.80 when total annual purchases = 0. (c) Which statement is correct concerning the quality of this model? A. 28.4% of the variability in…
In a fisheries researchers experiment the correlation between the number of eggs in tge nest and the number of viable (surviving ) eggs for a sample of nests is r=0.67 the equation of the regression line for number of viable eggs y versus number of eggs in the nest x is y =0.72x + 17.07 for a nest with 140 eggs what is the predicted number of viable eggs ?
A researcher studied the relationship between the amount of carbohydrates (x) and the amount of salt (y) in different food products. sample of 36 food products yielded these calculations: r = -0.1245, ŷ=0.5545– 0.1636x According to the correlation, if a food contains more carbohydrates, is it likely to contain more salt or less salt? Why or why not?
A sample of 60 women is obtained, and their heights (in inches) and pulse rates (in beats per minute) are measured. The linear correlation coefficient is 0.263 and the equation of the regression line is y=17.9+0.940x, where x represents height. The mean of the 60 heights is 63.3 in and the mean of the 60 pulse rates is 76.8 beats per minute. Find the best predicted pulse rate of a woman who is 67 in tall. Use a significance level of α=0.05.LOADING... Click the icon to view the critical values of the Pearson correlation coefficient r.Question content area bottomPart 1The best predicted pulse rate of a woman who is 67 in tall is enter your response here beats per minute. (Type an integer or decimal rounded to two decimal places as needed.)

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