Topic: Constant Temperature Packed Bed Reactor A gas phase rxn AP undergoes a constant temperature process in a PBR and follows the rate law given below. Derive the expression in order to solve XA (reactant A's conversion) as a function of weight for the catalyst. Determine the weight of the catalyst in order to get XA = 0.90 (90 percent), given CÃO = 0.95 moles/liter, initial volumetric flow rate (Vo) = 12.5 liters/minute, a = 0.0008/kilogram, k = 0.1- moles kilogram catalyst-minute-atm¹5 And P = 2 atmosphere Ao -TA' = K₂P₁ 1.5
Topic: Constant Temperature Packed Bed Reactor A gas phase rxn AP undergoes a constant temperature process in a PBR and follows the rate law given below. Derive the expression in order to solve XA (reactant A's conversion) as a function of weight for the catalyst. Determine the weight of the catalyst in order to get XA = 0.90 (90 percent), given CÃO = 0.95 moles/liter, initial volumetric flow rate (Vo) = 12.5 liters/minute, a = 0.0008/kilogram, k = 0.1- moles kilogram catalyst-minute-atm¹5 And P = 2 atmosphere Ao -TA' = K₂P₁ 1.5
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Topic: Constant Temperature Packed Bed Reactor
Transcribed Image Text:Topic: Constant Temperature Packed Bed Reactor
A gas phase rxn A → P undergoes a constant temperature process in a PBR and follows
the rate law given below. Derive the expression in order to solve XA (reactant A's conversion)
as a function of weight for the catalyst. Determine the weight of the catalyst in order to
get XA = 0.90 (90 percent), given CÃO = 0.95 moles/liter, initial volumetric flow rate
moles
(Vo) = 12.5 liters/minute, a = 0.0008/kilogram, k₁ = 0.1-
kilogram catalyst-minute-atm¹
And P = 2 atmosphere
Ao
1.5
-TA' = k₁P₁¹
1.5
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