Topic 16) The following data is based upon the results from the *Granite State Poll (New Hampshire polling center) made available on October 19th, 2020. The poll asked respondents about how stressed they were on a scale of 1 through 10 (10 being most stressed) regarding certain events in 2020. In April of 2020, a random sample of 1,002 New Hampshire residents were asked how stressed they were about Covid-19 and 57% of them answered 7 or greater. In October of 2020, a random sample of 899 New Hampshire residents were asked how stressed they were about the presidential election and 68% of them answered 7 or greater. Use this information to complete the hypothesis test claiming that the proportion of people who had a stress level of 7 or more regarding the presidential election was greater than those who had a stress level of 7 or more regarding the Covid-19 pandemic back in April at the 1% significance level. (a) What is the null hypothesis (H0), alternate hypothesis (H1), and tail type? (b) This problem is an example of a One-Sample Mean One-Sample Proportion Two-Sample Mean Two-Sample Proportion c) Find the test statistic related to this problem. d) Find the critical value and rejection region for α or the p-value of your test statistic. (e) Use your results sbove to determine whether you would reject or fail to reject the null hypothesis. (f) Which of the following is the best conclusion? The data provides evidence that the proportion of people who had a stress level of 7 or more regarding the presidential election was greater than those who had a stress level of 7 or more regarding the Covid-19 pandemic back in April. The data does not provide evidence that the proportion of people who had a stress level of 7 or more regarding the presidential election was greater than those who had a stress level of 7 or more regarding the Covid-19 pandemic back in April.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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(Topic 16) The following data is based upon the results from the *Granite State Poll (New Hampshire polling center) made available on October 19th, 2020. The poll asked respondents about how stressed they were on a scale of 1 through 10 (10 being most stressed) regarding certain events in 2020.

In April of 2020, a random sample of 1,002 New Hampshire residents were asked how stressed they were about Covid-19 and 57% of them answered 7 or greater. In October of 2020, a random sample of 899 New Hampshire residents were asked how stressed they were about the presidential election and 68% of them answered 7 or greater. Use this information to complete the hypothesis test claiming that the proportion of people who had a stress level of 7 or more regarding the presidential election was greater than those who had a stress level of 7 or more regarding the Covid-19 pandemic back in April at the 1% significance level.

(a) What is the null hypothesis (H0), alternate hypothesis (H1), and tail type?

(b) This problem is an example of a

One-Sample Mean
One-Sample Proportion
Two-Sample Mean
Two-Sample Proportion

c) Find the test statistic related to this problem.

d) Find the critical value and rejection region for α or the p-value of your test statistic.

(e) Use your results sbove to determine whether you would reject or fail to reject the null hypothesis.

(f) Which of the following is the best conclusion?

The data provides evidence that the proportion of people who had a stress level of 7 or more regarding the presidential election was greater than those who had a stress level of 7 or more regarding the Covid-19 pandemic back in April.
The data does not provide evidence that the proportion of people who had a stress level of 7 or more regarding the presidential election was greater than those who had a stress level of 7 or more regarding the Covid-19 pandemic back in April.

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Given:

${\hat{p}}_{1} = P r o p o r t i o n o f p e o p l e w i t h s t r e s s l e v e r o f 7 o r m o r e d u e t o C o v i d - 19 = 0.57 {\hat{p}}_{2} = P r o p o r t i o n o f p e o p l e w i t h s t r e s s l e v e r o f 7 o r m o r e d u e t o p r e s e d e n t i a l e l e c t i o n s = 0.68 n_{1} = S a m p l e s i z e f o r C o v i d - 19 = 1002 n_{2} = S a m p l e s i z e f o r p r e s e d e n t i a l e l e c t i o n s = 899$

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