Tollowin TABLE CUSTOMER Column Null? Туре CUS_ID NOT NULL NUMBER NAME VARCHAR2(58) CUS_PHONE VARCHAR2(50) REGION_ID NUMBER TABLE REGION Column Null? Туре REGION_ID NOT NULL NUMBER NAME VARCHAR2(50) The quesry that lists all customer rows (including the ones that have no matching regions) and all matching region rows Select cus_id, customer.name, region.name FROM customer NATURAL JOIN region on customer.region_id=region.region_id Select cus_id, customer.name, region.name b FROM customer RIGHT JOIN region on customer.region_id=region.region_id Select cus_id, customer.name, region.name FROM customer LEET JOIN region on cuustomer region id-region region id
Tollowin TABLE CUSTOMER Column Null? Туре CUS_ID NOT NULL NUMBER NAME VARCHAR2(58) CUS_PHONE VARCHAR2(50) REGION_ID NUMBER TABLE REGION Column Null? Туре REGION_ID NOT NULL NUMBER NAME VARCHAR2(50) The quesry that lists all customer rows (including the ones that have no matching regions) and all matching region rows Select cus_id, customer.name, region.name FROM customer NATURAL JOIN region on customer.region_id=region.region_id Select cus_id, customer.name, region.name b FROM customer RIGHT JOIN region on customer.region_id=region.region_id Select cus_id, customer.name, region.name FROM customer LEET JOIN region on cuustomer region id-region region id
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
Related questions
Question
q18
Transcribed Image Text:Given the following tables
TABLE CUSTOMER
Column
Null?
Туре
CUS_ID
NOT NULL NUMBER
NAME
VARCHAR2(58)
CUS_PHONE
VARCHAR2(50)
REGION_ID
NUMBER
TABLE REGION
Column
Null?
Туре
REGION_ID NOT NULL NUMBER
VARCHAR2 (50)
NAME
The quesry that lists all customer rows (including the ones that have no matching regions) and all
matching region rows
Select cus_id, customer.name, region.name
a O
FROM customer NATURAL JOIN region on customer.region_id=region.region_id
Select cus_id, customer.name, region.name bo
FROM customer RIGHT JOIN region on customer.region_id=region.region_id
Select cus_id, customer.name, region.name
.CO
FROM customer LEFT JOIN region on customer.region_id=region.region_id
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