Please explain what tables are used to find the answers. Problem 2.Today's weather calls for a relative humidity of 90% and the dew point is 25°C.Determine thespecific humidity and partial pressure of water vapor and air. If thevolume of the room is 15 m³ how much is the mass of water vapor and dry air?What is the enthalpy of the air mixture?The atmospheric air pressure is 101.3 kPa do not use psychometric charts

Relative Humidity: Relative Humidity (RH) is defined as the ratio of partial pressure of water vapor, pw, in a mixture to the saturation pressure, ps, of pure water, at the same temperature of the mixture. The relative is represented by the symbol, ϕ The mathematical relation for the relative humidity is, RH(ϕ)=pwps where the variables have their usual meaning. Specific Humidity: Specific Humidity or humidity ratio, W, is defined as the mass of water vapor (moisture) per unit mass of dry air in a mixture of air and water vapor. The mathematical relation for specific humidity is W=0.622pwp-pw where p is the atmospheric pressure Writing the relevant information given in the question: Relative humidity of the mixture, RH=90% or 0.9 Dew point temperature of the mixture, TDP=25°C=25+273=298K The volume of the mixture, V=15m3 The atmospheric pressure of the mixture, patm=101.3kPa Now, taking the value of saturation pressure of water at 298K, ps=0.0313×101.3=3.1707kPa Now, calculating the partial pressure of water vapor as: RH=pwps0.9=pw3.1707pw=2.8526kPa Thus, the specific humidity of the mixture be: W=0.622pwp-pwW=0.622×2.8526101.3-2.8526W=0.01803 kgkg of air Now, apply the ideal gas equation to the mixture, to calculate the total mass of the mixture: PV=mTRT101.325×15=mT×0.287×298mT=17.76kg The mass of dry air becomes: G=mT-WG=17.76-0.01803G=17.74kg Now, calculating the enthalpy of the mixture at the given temperature as: Gh=Gha+mhw17.74×h=17.74×299.49+0.01803×285.76h=300.8kJkg 1. The Specific Humidity of the mixture be 0.01803 kg/kg of dry air. 2. The Partial pressure of the water vapor in the mixture be 2.8526kPa. 3. The mass of dry air in the mixture be 17.74kg. 4. The Enthalpy per kg of the mixture at the given state is 300.8 kJ/kg.