Today, the waves are crashing onto the beach every 4.9 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 4.9 seconds. Round to 4 decimal places where possible. a. The mean of this distribution is b. The standard deviation is c. The probability that wave will crash onto the beach exactly 4.2 seconds after the person arrives is P(x - 4.2) -

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Chapter1: Combinatorial Analysis
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Today, the waves are crashing onto the beach every 4.9 seconds. The times from when a person arrives at
the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 4.9 seconds. Round
to 4 decimal places where possible.
a. The mean of this distribution is
b. The standard deviation is
c. The probabitity that wave will crash onto the beach exactly 4.2 seconds after the person arrives is
P(x - 4.2) -
d. The probability that the wave will crash onto the beach between 1.4 and 2 seconds after the person
arrives is P(1.4 < x < 2) -
e. The probability that it will take longer than 3.58 seconds for the wave to crash onto the beach after
the person arrives is P(x > 3.58) =
f. Find the maximum for the lower quartile.
seconds.
Transcribed Image Text:Today, the waves are crashing onto the beach every 4.9 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 4.9 seconds. Round to 4 decimal places where possible. a. The mean of this distribution is b. The standard deviation is c. The probabitity that wave will crash onto the beach exactly 4.2 seconds after the person arrives is P(x - 4.2) - d. The probability that the wave will crash onto the beach between 1.4 and 2 seconds after the person arrives is P(1.4 < x < 2) - e. The probability that it will take longer than 3.58 seconds for the wave to crash onto the beach after the person arrives is P(x > 3.58) = f. Find the maximum for the lower quartile. seconds.
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