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TO001235 T0101405 T0131735 T0001038 T0201230 T0807000 T0201203 T2374005 T4070745 T4072307 Insert this using separate chaining (open hashing) in the hashtable below Table of 23 elements 0: nullpr 1: T20107424 2: nullptr 3: nullptr 4: T3290334 →- TO000284 5: nullptr 6: T0314303 7: nullptr etc. 8: pullptr -.... 21: nullptr 22: nullptr

TO001235 T0101405 T0131735 T0001038 T0201230 T0807000 T0201203 T2374005 T4070745 T4072307 Insert this using separate chaining (open hashing) in the hashtable below Table of 23 elements 0: nullpr 1: T20107424 2: nullptr 3: nullptr 4: T3290334 →- TO000284 5: nullptr 6: T0314303 7: nullptr etc. 8: pullptr -.... 21: nullptr 22: nullptr

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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How would the table look like if we used separate chaining (open hashing)

### Problem Statement Insert the following keys using separate chaining (open hashing) in the hash table below: - T0001235 - T0101405 - T0131735 - T0001038 - T0201230 - T0807000 - T0201203 - T2374005 - T4070745 - T4072307 ### Hash Table Structure #### Table of 23 Elements - **Index 0:** `nullptr` - **Index 1:** `nullptr` → T20107424 - **Index 2:** `nullptr` - **Index 3:** `nullptr` - **Index 4:** `nullptr` → T3290334 → T0000284 - **Index 5:** `nullptr` - **Index 6:** `nullptr` → T0314303 - **Index 7:** `nullptr` - **Index 8:** and so on (`etc.`) - **Index 21:** `nullptr` - **Index 22:** `nullptr` ### Diagram Explanation The diagram illustrates a hash table using separate chaining, where collisions are handled by linking elements in a list. Each index in the table has either `nullptr` for empty slots or a linked structure showing the keys stored at that index. For example, at index 4, two keys are chained: T3290334 and T0000284. Using open hashing, multiple keys can be stored at the same index without overwriting.
Transcribed Image Text:### Problem Statement Insert the following keys using separate chaining (open hashing) in the hash table below: - T0001235 - T0101405 - T0131735 - T0001038 - T0201230 - T0807000 - T0201203 - T2374005 - T4070745 - T4072307 ### Hash Table Structure #### Table of 23 Elements - **Index 0:** `nullptr` - **Index 1:** `nullptr` → T20107424 - **Index 2:** `nullptr` - **Index 3:** `nullptr` - **Index 4:** `nullptr` → T3290334 → T0000284 - **Index 5:** `nullptr` - **Index 6:** `nullptr` → T0314303 - **Index 7:** `nullptr` - **Index 8:** and so on (`etc.`) - **Index 21:** `nullptr` - **Index 22:** `nullptr` ### Diagram Explanation The diagram illustrates a hash table using separate chaining, where collisions are handled by linking elements in a list. Each index in the table has either `nullptr` for empty slots or a linked structure showing the keys stored at that index. For example, at index 4, two keys are chained: T3290334 and T0000284. Using open hashing, multiple keys can be stored at the same index without overwriting.
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