To use the principle of linear impulse and momentum to relate a force on an object to the resulting velocity of the object at different times. The equation of motion for a particle of mass m can be written as ∑F=ma=mdvdt By rearranging the terms and integrating, this equation becomes the principle of linear impulse and momentum: ∑∫t2t1Fdt=m∫v2v1dv=mv2−mv1 For problem-solving purposes, this principle is often rewritten as mv1+∑∫t2t1Fdt=mv2 The integral ∫Fdt is called the linear impulse, I, and the vector mv is called the particle's linear momentum. A stop block, s, prevents a crate from sliding down a θ = 20.0 ∘ incline. (Figure 1) A tensile force F=(F0t) N acts on the crate parallel to the incline, where F0 = 265 N/s . If the coefficients of static and kinetic friction between the crate and the incline are μs = 0.290 and μk = 0.195, respectively, and the crate has a mass of 57.4 kg , how long will it take until the crate reaches a velocity of 3.01 m/s as it moves up the incline?
To use the principle of linear impulse and momentum to relate a force on an object to the resulting velocity of the object at different times.
The equation of motion for a particle of mass m
can be written as
∑F=ma=mdvdt
By rearranging the terms and integrating, this equation becomes the principle of linear impulse and momentum:
∑∫t2t1Fdt=m∫v2v1dv=mv2−mv1
For problem-solving purposes, this principle is often rewritten as
mv1+∑∫t2t1Fdt=mv2
The integral ∫Fdt is called the linear impulse, I, and the
A stop block, s, prevents a crate from sliding down a θ = 20.0 ∘ incline. (Figure 1) A tensile force F=(F0t) N acts on the crate parallel to the incline, where F0 = 265 N/s . If the coefficients of static and kinetic friction between the crate and the incline are μs = 0.290 and μk = 0.195, respectively, and the crate has a mass of 57.4 kg , how long will it take until the crate reaches a velocity of 3.01 m/s as it moves up the incline?
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