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To use the method of partial fractions, which one is the correct set up before computing the constants? B (2²+1)(2-1)² = 2²4+1+1+ (1²+1)(x-1)² (²+1)(z-1)² (z²+1)(z-1)² = == = Az+B Az+B Az+B ²+1 ++ 29 G (z-1)² (z-1)² (x-1) Dr+E (T-1)²

To use the method of partial fractions, which one is the correct set up before computing the constants? B (2²+1)(2-1)² = 2²4+1+1+ (1²+1)(x-1)² (²+1)(z-1)² (z²+1)(z-1)² = == = Az+B Az+B Az+B ²+1 ++ 29 G (z-1)² (z-1)² (x-1) Dr+E (T-1)²

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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To use the method of partial fractions, which one is the correct set up before computing the constants? -2x+4 B (2²+1)(2-1)² = 2²4+1+₁+ (z²+1)(x-1)² (²+1)(z-1)² (z²+1)(z-1)² = == = Az+B ²+1 Az+B Az+B ²+1 ++ 99 (z-1)² (z-1)² (x-1) Da E (2-1)²
Transcribed Image Text:To use the method of partial fractions, which one is the correct set up before computing the constants? -2x+4 B (2²+1)(2-1)² = 2²4+1+₁+ (z²+1)(x-1)² (²+1)(z-1)² (z²+1)(z-1)² = == = Az+B ²+1 Az+B Az+B ²+1 ++ 99 (z-1)² (z-1)² (x-1) Da E (2-1)²
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