To test whether the mean time needed to mix a batch of material is the same for machines produced by three manufacturers, the Jacobs Chemical Company obtained the following data on the time(in minutes) needed to mix the material.Manufacturer12213119272918253422233021Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means for manufacturer 1 and manufacturer 2. Round to two decimal places. Enter negativevalues as negative numbers.to

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Answered: To test whether the mean time needed to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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To test whether the mean time needed to mix a batch of material is the same for machines produced by three manufacturers, the Jacobs Chemical Company obtained the following data on the time (in minutes) needed to mix the material. Manufacturer 1 2 3 19 32 23 25 30 22 23 35 26 21 31 25 a. Use these data to test whether the population mean times for mixing a batch of material differ for the three manufacturers. Use alpha=0.05. Compute the values below (to 2 decimals, if necessary). Sum of Squares, Treatment ? Sum of Squares, Error ? Mean Squares, Treatment ? Mean Squares, Error ? Calculate the value of the test statistic (to2 decimals)? The p-value is? What is your conclusion? b. At the 0.05 level of significance, use Fisher's LSD procedure to test for the equality of the means for manufacturers 1 and 3. Calculate Fisher's LSD Value (to 2 decimals)? What conclusion can you draw after carrying out this test?
2.18 2.42 2.57 2.89 Suppose the data represent the inches of rainfall in April for a certain city over the course of 20 years. 4.79 D 0.53 0.76 1.23 1.37 1.86 3.37 3.66 3.88 4.09 4.49 5.04 5.36 5.79 Given the quartiles Q, = 2.020, Q, = 3.280, and Q3 = 4.640, compute the interquartile range, IQR. 3.19 6.08 IQR =D (Round to three decimal places as needed.)
Answer A B C
Medical research has shown that repeated wrist extensions beyond 20 degrees increase the risk of wrist and hand injuries. Each of 24 students at a university used a proposed new computer mouse design, and while using the mouse, each student's wrist extension was recorded. Data consistent with summary values given in a paper are given here. 27 22 29 24 27 27 25 25 24 24 24 25 28 25 24 28 27 26 31 25 28 27 27 25 USE SALT (a) Use these data to estimate the mean wrist extension for people using this new mouse design using a 90% confidence interval. (Round your answers to three decimal places.)
Import the data from the Hill City Excel file into Minitab.You are trying to predict Price.Note: Mtn View=1 if there is a mountain view, 0 otherwise. The rest of the variables should be self explanatory. 1.Perform an F Test for overall significance of the model 2.Perform a T test for slope for the age variable 3. Find a 95% confidence interval for the slope of the SqFeet variable4. Create a prediction, CI, and PI for 1 new set of x values (any valid numbers you want), and interpret each.5. Run the residual plots and indicate if they show any problems with the model.
In the following Table are gradients for eight female teeth and eight male teeth. These numbers are measures of the rate of change in the amount of X-ray penetration through a 500-micron section of tooth enamel at a wavelength of 600 nm as opposed to 400 nm. Find the 95% confidence interval for lx - ly. Hint(to.025,14 =2.1448) Male Xi 4.9 5.4 4.8 5.3 5.0 5.5 5.4 6.6 6.3 4.3 Female y; 3.7 4.1 5.6 4.0 3.6 5.0
Data for fuel economy ratings in mi/gal for different cars are listed below. Each pair of data represents the rating using the Old test and the New test. Old (x) 31 22 23 33 27 21 22 19 31 16 New (y) 25 17 26 26 23 18 19 16 28 19 Find the best predicted value for the New test method given that the Old test method rating was 26. Use a significance level of 0.05.Round your answer to 1 decimal place, if needed.
Given two independent random samples with the following results: n₂ = 8 x₂ = 175 $2 = 11 n₁ = 12 x₁ = = 157 $₁ = 32 Use this data to find the 95% confidence interval for the true difference between the population means. Assume that the population variances are not equal and that the two populations are normally distributed. Copy Data Step 1 of 3: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.

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