kindly explain the terms and formulas used in this picture! (c)To test our hypothesis:Họ : B1 = B3 against H1 : B1 + 33We first need to find the least squares estimates of the parameters. We will write our modelas:y = XB+ €, €n N(0,o².I)Then3 = (X'X)-'(X'y)We also know that,MSEB~ N(8,02(X'X)-'),~ Xn-5Note that the degrees of freedom are n-5 because there are 5 parameters (90, B1,..., B5) thatare estimated.. B1 - B - N(3, – B3, (s" + s* - 2s³ )o²) where s" is the (i)-th element of(XX)!.and they are independent...T =tn-5 under HoVMSEVS"25Using the above test statistic, we reject Ho at level of significance a ifobserved |t| > ta;n-5

Name: kindly explain the terms and formulas used in this picture! (c)To test
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Description: kindly explain the terms and formulas used in this picture! (c)To test our hypothesis:Họ : B1 = B3 against H1 : B1 + 33We first need to find the least squares estimates of the parameters. We will write our modelas:y = XB+ €, €n N(0,o².I)Then3 = (X'X)

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To test our hypothesis: Họ : Bị = Ba against H1 : B1 + Ba We first need to find the least squares estimates of the parameters. We will write our model as: y - X3 + e, e~ N(0, o².1) Then 3 = (X'X)-'(X'y) We also know that, MSE B~ N(3,0°(X'X)-'), Note that the degrees of freedom are n-5 because there are 5 parameters (%, 31,... , B5) that are estimated. .. B - Ba- N(31 – Ba, (s" + s* – 2s" J²) where s is the ()-ta element of (X'Xy!. and they are independent. ..T = n tn-5 under Ho VMSEVS" + 3 – 2s3 Using the above test statistic, we reject Ho at level of significance a if observed |t| > taçn-5

To test our hypothesis: Họ : Bị = Ba against H1 : B1 + Ba We first need to find the least squares estimates of the parameters. We will write our model as: y - X3 + e, e~ N(0, o².1) Then 3 = (X'X)-'(X'y) We also know that, MSE B~ N(3,0°(X'X)-'), Note that the degrees of freedom are n-5 because there are 5 parameters (%, 31,... , B5) that are estimated. .. B - Ba- N(31 – Ba, (s" + s* – 2s" J²) where s is the ()-ta element of (X'Xy!. and they are independent. ..T = n tn-5 under Ho VMSEVS" + 3 – 2s3 Using the above test statistic, we reject Ho at level of significance a if observed |t| > taçn-5

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Concept explainers

Permutations and Combinations

If there are 5 dishes, they can be relished in any order at a time. In permutation, it should be in a particular order. In combination, the order does not matter. Take 3 letters a, b, and c. The possible ways of pairing any two letters are ab, bc, ac, ba, cb and ca. It is in a particular order. So, this can be called the permutation of a, b, and c. But if the order does not matter then ab is the same as ba. Similarly, bc is the same as cb and ac is the same as ca. Here the list has ab, bc, and ac alone. This can be called the combination of a, b, and c.

Counting Theory

The fundamental counting principle is a rule that is used to count the total number of possible outcomes in a given situation.

Topic Video

Question

kindly explain the terms and formulas used in this picture!

(c)
To test our hypothesis:
Họ : B1 = B3 against H1 : B1 + 33
We first need to find the least squares estimates of the parameters. We will write our model
as:
y = XB+ €, €n N(0,o².I)
Then
3 = (X'X)-'(X'y)
We also know that,
MSE
B~ N(8,02(X'X)-'),
~ Xn-5
Note that the degrees of freedom are n-5 because there are 5 parameters (90, B1,..., B5) that
are estimated.
. B1 - B - N(3, – B3, (s" + s* - 2s³ )o²) where s" is the (i)-th element of
(XX)!.
and they are independent.
..T =
tn-5 under Ho
VMSEVS"
25
Using the above test statistic, we reject Ho at level of significance a if
observed |t| > ta;n-5

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