To study the output of a machine that fills boxes with cereal, a quality control engineer weighed 150 boxes of Brand X cereal. The frequency distribution in the following table summarizes his findings. Find the standard deviation of the weight of the boxes of cereal. (Round your answer to three decimal places.) ___oz x = Weight (ounces) Number of boxes 15.3 ≤ x < 15.6 11 15.6 ≤ x < 15.9 24 15.9 ≤ x < 16.2 85 16.2 ≤ x < 16.5 17 16.5 ≤ x < 16.8 13

To study the output of a machine that fills boxes with cereal, a quality control engineer weighed 150 boxes of Brand X cereal. The frequency distribution in the following table summarizes his findings. Find the standard deviation of the weight of the boxes of cereal. (Round your answer to three decimal places.) ___oz x = Weight (ounces) Number of boxes 15.3 ≤ x < 15.6 11 15.6 ≤ x < 15.9 24 15.9 ≤ x < 16.2 85 16.2 ≤ x < 16.5 17 16.5 ≤ x < 16.8 13

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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x = Weight (ounces)	Number of boxes
15.3 ≤ x < 15.6	11
15.6 ≤ x < 15.9	24
15.9 ≤ x < 16.2	85
16.2 ≤ x < 16.5	17
16.5 ≤ x < 16.8	13

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Still need D , E and F
Hi please assist
Excel's O a. COUNTIF function Ob. AVERAGE function O c. PivotTable report O d. SUM function can be used to construct a frequency distribution for quantitative data.
The authors of a paper were interested in how the distance a deer mouse will travel for food is related to the distance from the food to the nearest pile of debris. Distances were measured in meters. The data and computer output are given below. Distance from Debris Distance Traveled 6.94 0.00 5.23 6.13 5.21 11.29 7.10 14.35 8.16 12.03 5.50 22.72 9.19 20.11 9.05 26.16 9.36 30.65 Simple Linear Regression Results: Dependent Variable: Traveled Independent Variable: Debris Sample size: 9 R (correlation coefficient) = 0.5657 R-sq = 0.32002088 Estimate of error standard deviation 8.670711 Parameter estimates: Parameter Estimate Std. Err. Alternative DF T-Stat P-Value Intercept -7.6854587 13.332196 ≠ 0 7 -0.5764586 0.5824 Slope 3.2340908 1.7818117 ≠ 0 7 1.8150575 0.1124 a)What is the least squares regression line for the output given above? b) what is the predicted traveled distance given the distance from debris is 6.5 meters?
1:15 (a) Which variable is the explanatory variable? OA. One of the biggest factors in determining the value of a home is the square footage. The accompanying data represent the square footage and selling price (in thousands of dollars) for a random sample of homes for sale in a certain region. Complete parts (a) through (h) below. Click the icon to view the housing data. Square Footage Selling Price (b) Draw a scatter diagram of the data. Choose the correct scatter diagram below. Ay 4500- 000 1000 mylab.pearson.com/ + ® : 3 4500 Data Table Q Square Footage, x 2148 3231 1177 1988 3064 2735 4146 2215 2625 1629 1773 3887 Print ||| OB. r= 0.899 (Round to three decimal places as needed.) = AX 4500- 1000+++ 150 750 Q (c) Determine the linear correlation coefficient between square footage and asking price. Done Ay 750- Vo) 1 LTE2 150- O 1000 Selling Price ($000s), y D 371.1 382.2 197.6 339.9 614.9 364.7 632.7 377.7 427.5 285.9 268.9 701.4 4500 .... .... Q X D. Ay 750- 41% 150+ 1000 4500
Speed cameras (SC) are used to reduce the risk of accidents in accident-prone zones in metropolitan cities. To study the effectiveness of speed cameras, transport engineers would like to compare the average number of accidents in junction A (with SC) and junction B (without SC). The number of accidents in 105 weeks in two junctions are provided below. 6 7+ Number of Accidents 0 1 2 3 4 5 Observed frequency 40 20 15 16 10 3 1 0 Number of Accidents 0 1 2 3 4 5 6 7+ Junction B without SC Observed frequency 25 24 18 15 18 41 0 Junction A with SC Test the average number of accidents per week in junctions A and B are same at the 5% significance level.
Summarize the frequency, the total dollars spent, and the mean amount spent per transaction for each type of browser. Discuss the observation you can make about heavenly chocolates business based on the type of browser?
Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 52.5 degrees. Low Temperature (o F) 40 - 44 45 - 49 50 - 54 55 - 59 60 – 64 D Frequency 2 9. ... The mean of the frequency distribution is degrees. (Round to the nearest tenth as needed.) Which of the following best describes the relationship between the computed mean and the actual mean? O A. The computed mean is close to the actual mean because the difference between the means is more than 5% of the actual mean. B. The computed mean is not close to the actual mean because the difference between the means is less than 5% of the actual mean. C. The computed mean is not close to the actual mean because the difference between the means is more than 5% of the actual mean. D. The computed mean is close to the actual mean because the difference between the means is less than 5% of the actual mean.
Recall the histogram of annual maximum wind speed. Frequency оооооо 25 to 30 30 to <35 35 to 40 A histogram with a single peak is unimodal. A histogram with two peaks is bimodal. A histogram with more than two peaks is multimodal. Look over the histogram again and notice the number of peaks, or modes, in the distribution. Indicate below the class interval(s) where a peak occurs. (Select all that apply.) 40 to 45 45 to < 50 50 to < 55 55 to < 60 14 12 10 60 to < 65 co 4 25 30 35 40 45 50 55 60 65 annual maximum wind speed
What is the appropriate measure of center for these data? O A. Mode OB. Range OC. Mean O D. Median O E. Skew 1525 54 1 5 2 6 5 4 3 19 8 7 6 4 4345656 7 6 9