To strengthen his arm and chest muscles, an 85-kg athlete 2.0 m tall is doing a series of push-ups as shown in the figure below (Figure 1). His center of mass is 1.10 m from the bottom of his feet, and the Part A centers of his palms are 30.0 cm from the top of his head. Find the force that the floor exerts on each of his feet, assuming that both feet exert the same force. Express your answer in newtons. ? F = 265.5 N Submit Previous Answers Request Answer X Incorrect; Try Again Part B Figure 1 of 1 > Find the force that the floor exerts on each of his hands, assuming both palms exert the same force. Express your answer in newtons. 2.0 m F = 147 N - 30.0 cm - Submit Previous Answers Request Answer X Incorrect; Try Again

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Need help with this question keep getting an incorrect answer. I keep getting around 269.5 for A and 147 for B.

**Educational Content: Understanding Forces During Push-Ups**

To strengthen his arm and chest muscles, an 85-kg athlete who is 2.0 m tall is performing a series of push-ups, as depicted in the figure below (Figure 1). The athlete's center of mass is located 1.10 m from the bottom of his feet, and the centers of his palms are positioned 30.0 cm from the top of his head.

**Part A**

Objective: Determine the force that the floor exerts on each of the athlete's feet, assuming both feet exert the same force. Express your answer in newtons.

- Calculated Force: 265.5 N
- Status: Incorrect; Try Again

**Part B**

Objective: Determine the force that the floor exerts on each of the athlete's hands, assuming both palms exert the same force. Express your answer in newtons.

- Calculated Force: 147 N
- Status: Incorrect; Try Again

**Figure Explanation**

The diagram illustrates an athlete in a push-up position. The total length of the athlete is 2.0 meters, with a measurement of 30.0 cm from the top of the head to the palms. This setup helps in calculating the distribution of forces exerted on the hands and feet during the exercise.
Transcribed Image Text:**Educational Content: Understanding Forces During Push-Ups** To strengthen his arm and chest muscles, an 85-kg athlete who is 2.0 m tall is performing a series of push-ups, as depicted in the figure below (Figure 1). The athlete's center of mass is located 1.10 m from the bottom of his feet, and the centers of his palms are positioned 30.0 cm from the top of his head. **Part A** Objective: Determine the force that the floor exerts on each of the athlete's feet, assuming both feet exert the same force. Express your answer in newtons. - Calculated Force: 265.5 N - Status: Incorrect; Try Again **Part B** Objective: Determine the force that the floor exerts on each of the athlete's hands, assuming both palms exert the same force. Express your answer in newtons. - Calculated Force: 147 N - Status: Incorrect; Try Again **Figure Explanation** The diagram illustrates an athlete in a push-up position. The total length of the athlete is 2.0 meters, with a measurement of 30.0 cm from the top of the head to the palms. This setup helps in calculating the distribution of forces exerted on the hands and feet during the exercise.
### Transcription and Explanation

The image contains a diagram and some equations related to forces and balance:

#### Diagram Explanation

1. **Diagram Structure:**
   - A horizontal beam or object is shown.
   - Two forces are acting on it, labeled as \( F_{\text{foot}} \) (on the left) and \( F_{\text{hands}} \) (on the right).

2. **Measurements and Labels:**
   - The total length of the beam is divided into two segments: 
     - Left segment: \( 1.1 \) meters from the left end.
     - Right segment: \( 3 \) meters from the right end.
   - The position marked 'cm' seems to denote the center of mass (though it is not clearly labeled as such).

3. **Additional Elements:**
   - \( W \), possibly indicating weight, is acting downward at the center point of the beam.
   - The entire span between the left and right endpoints is 2 meters.

#### Equations

1. \( F_{\text{feet}} = 2 \cdot F_y \text{ foot} \)

2. \( F_{\text{hands}} = 2 \cdot F_{\text{each hand}} \)

#### Second Diagram

- A follow-up sketch shows another object, possibly a lever or bar:
  - Labeled 'm' with a force \( m \) acting upwards in the middle.
  - The total span seems to be denoted as \( m, 2 \).

This content could be related to a lesson on balance of forces, torque, or mechanical equilibrium, illustrating how forces are distributed in a lever system or bipod balance.
Transcribed Image Text:### Transcription and Explanation The image contains a diagram and some equations related to forces and balance: #### Diagram Explanation 1. **Diagram Structure:** - A horizontal beam or object is shown. - Two forces are acting on it, labeled as \( F_{\text{foot}} \) (on the left) and \( F_{\text{hands}} \) (on the right). 2. **Measurements and Labels:** - The total length of the beam is divided into two segments: - Left segment: \( 1.1 \) meters from the left end. - Right segment: \( 3 \) meters from the right end. - The position marked 'cm' seems to denote the center of mass (though it is not clearly labeled as such). 3. **Additional Elements:** - \( W \), possibly indicating weight, is acting downward at the center point of the beam. - The entire span between the left and right endpoints is 2 meters. #### Equations 1. \( F_{\text{feet}} = 2 \cdot F_y \text{ foot} \) 2. \( F_{\text{hands}} = 2 \cdot F_{\text{each hand}} \) #### Second Diagram - A follow-up sketch shows another object, possibly a lever or bar: - Labeled 'm' with a force \( m \) acting upwards in the middle. - The total span seems to be denoted as \( m, 2 \). This content could be related to a lesson on balance of forces, torque, or mechanical equilibrium, illustrating how forces are distributed in a lever system or bipod balance.
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