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To start the 12A 240V motor from the last problem you must reduce the starting current from the power source to 2 times the running current. To do that you have installed a starter with a starter resistor as shown below. This resistor is in the circuit until the switch shown is closed which shorts out the resistor. What size resistor must you use for the resistor (Ohms and Watts)? Starter Resistor = Starter Resistor = Ω W +o 240V 000 1200 STARTER 0.30 E 0.750

To start the 12A 240V motor from the last problem you must reduce the starting current from the power source to 2 times the running current. To do that you have installed a starter with a starter resistor as shown below. This resistor is in the circuit until the switch shown is closed which shorts out the resistor. What size resistor must you use for the resistor (Ohms and Watts)? Starter Resistor = Starter Resistor = Ω W +o 240V 000 1200 STARTER 0.30 E 0.750

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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**Starting a Motor with a Starter Resistor** To successfully start a 12A, 240V motor, it's essential to lower the starting current from the power source to twice the running current. This can be achieved by incorporating a starter with a resistor, as depicted in the diagram. ### Diagram Explanation: - **Power Source**: 240V DC is supplied. - **Components**: - **Starter Resistor**: Integrated into the circuit and only bypassed when the switch is closed. - **Additional Resistors**: A 0.3Ω resistor and a 0.75Ω resistor are in series with the motor. - **Motor**: Denoted by \( E_g \). ### Calculation Requirements: Determine the appropriate values for the starter resistor in terms of: - **Resistance** in Ohms (Ω) - **Power Rating** in Watts (W) This set-up ensures controlled starting conditions for the motor, preventing excessive current draw and potential damage. The starter resistor is crucial as it temporarily limits the current until normal running conditions are met, where it is then bypassed by the switch.
Transcribed Image Text:**Starting a Motor with a Starter Resistor** To successfully start a 12A, 240V motor, it's essential to lower the starting current from the power source to twice the running current. This can be achieved by incorporating a starter with a resistor, as depicted in the diagram. ### Diagram Explanation: - **Power Source**: 240V DC is supplied. - **Components**: - **Starter Resistor**: Integrated into the circuit and only bypassed when the switch is closed. - **Additional Resistors**: A 0.3Ω resistor and a 0.75Ω resistor are in series with the motor. - **Motor**: Denoted by \( E_g \). ### Calculation Requirements: Determine the appropriate values for the starter resistor in terms of: - **Resistance** in Ohms (Ω) - **Power Rating** in Watts (W) This set-up ensures controlled starting conditions for the motor, preventing excessive current draw and potential damage. The starter resistor is crucial as it temporarily limits the current until normal running conditions are met, where it is then bypassed by the switch.
Expert Solution
Step 1

Given : To reduce the starting current from the power source to 2 times the running current.

And Running current = 12 amp 

So, starting current will be = 12/2 = 6 amp 

To find the size of Starter resistor?

 

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