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To solve we first rewrite the equation in the form and then It follows that the equation is then we obtain which is is an where A=-2 A=3 y' = e²+y-1 dye²+y-1, dz (1-e²-y)dx + dy = 0. μ(x) = e ² e (1-e²-y)dr+edy = 0, H(z) y=ce² +e²² + A A=2 If we choose Hence, the function We solve this last problem to obtain A=1 full A=-1 multiplicator integrating factor exact not exact A=-3

To solve we first rewrite the equation in the form and then It follows that the equation is then we obtain which is is an where A=-2 A=3 y' = e²+y-1 dye²+y-1, dz (1-e²-y)dx + dy = 0. μ(x) = e ² e (1-e²-y)dr+edy = 0, H(z) y=ce² +e²² + A A=2 If we choose Hence, the function We solve this last problem to obtain A=1 full A=-1 multiplicator integrating factor exact not exact A=-3

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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To solve we first rewrite the equation in the form and then It follows that the equation is then we obtain which is is an where A=-2 A=3 y' = e²+y-1 dye²+y-1, dz (1-e²-y)dx + dy = 0. μ(x) = e ² e (1-e²-y)dr+edy = 0, H(z) y=ce² +e²² + A A=2 If we choose Hence, the function We solve this last problem to obtain A=1 full A=-1 multiplicator integrating factor exact not exact A=-3
Transcribed Image Text:To solve we first rewrite the equation in the form and then It follows that the equation is then we obtain which is is an where A=-2 A=3 y' = e²+y-1 dye²+y-1, dz (1-e²-y)dx + dy = 0. μ(x) = e ² e (1-e²-y)dr+edy = 0, H(z) y=ce² +e²² + A A=2 If we choose Hence, the function We solve this last problem to obtain A=1 full A=-1 multiplicator integrating factor exact not exact A=-3
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