To solve: The system starting from xo = [1 1 1] in three steps and up to 6S computation by Gauss- Seidel iteration. The approximation of the solution after three steps is x₁ = 6.39734, x2 = 3.6 and x3 = 1.119335. Calculation: The given equation is: 4x1-x2 = 22 -X1 +4x3 = -2.4 Rearrange the above equations is given below: x₁ = 0.25x2 +5.5 x2 = 0.25x3 + 3.35 x3 = 0.25x1 - 0.48 Using Gauss-Seidel iteration method to solve this system. x (m+1) 0.25x2 (m) +5.5 (m+1) x2 = 0.25x3 (m) +3.35 (m+1) = X3 - 0.48 4x2-x3 = 13.4 0.25x (m)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Can someone help me how did the 0.25 values and the constant values were derived in the highlighted part? thank you so much.

To solve: The system starting from Xo = [1 1 1] in three steps and up to 6S computation by Gauss-
Seidel iteration.
The approximation of the solution after three steps is x₁ = 6.39734, x2 = 3.6 and x3 = 1.119335.
Calculation:
The given equation is:
4x1-x2
= 22
4x2x3 = 13.4
-X1
+ 4x3
= -2.4
Rearrange the above equations is given below:
x₁ =
0.25x2
+ 5.5
x2 =
0.25x3 + 3.35
x3 = 0.25x1
- 0.48
Using Gauss-Seidel iteration method to solve this system.
Xy (m+1)
0.25x2 (m)
+5.5
X₂ (m+1) =
0.25x3(m)
+ 3.35
X3
- 0.48
(m+1) = 0.25x₁(m)
Transcribed Image Text:To solve: The system starting from Xo = [1 1 1] in three steps and up to 6S computation by Gauss- Seidel iteration. The approximation of the solution after three steps is x₁ = 6.39734, x2 = 3.6 and x3 = 1.119335. Calculation: The given equation is: 4x1-x2 = 22 4x2x3 = 13.4 -X1 + 4x3 = -2.4 Rearrange the above equations is given below: x₁ = 0.25x2 + 5.5 x2 = 0.25x3 + 3.35 x3 = 0.25x1 - 0.48 Using Gauss-Seidel iteration method to solve this system. Xy (m+1) 0.25x2 (m) +5.5 X₂ (m+1) = 0.25x3(m) + 3.35 X3 - 0.48 (m+1) = 0.25x₁(m)
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