to show that the numbers in question are incongruent modulo n.] 11. Verify that 0, 1, 2, 22, 23, ..., 2° form a complete set of residues modulo 11, but that 0, 12, 22, 32,.. 12. Prove the following 102 do not.

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Chapter2: Second-order Linear Odes
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11 . Short and simplified.
18. If a =b (mod n1) and a =c (mod n2), prove that b =c (mod n), where the integer
(a) 7|52n +3-2 5n –2
(b) 13|3"+2 + 42n+1.
(c) 27|25n+1 + 5n+2_
(d) 43 6+2 +72n+1.
7. For n > 1, show that
4.3
One
spec
hear
to in
(-13)"+1 = (-13)" + (-13)"- (mod 181)
sys
inte
[Hint: Notice that (-13)2 = -13 +1 (mod 181); use induction on n.]
8. Prove the assertions below:
(a) If a is an odd integer, then a? = 1 (mod 8).
(b) For any integer a, a³ = 0, 1, or 6 (mod 7).
(c) For any integer a, a* = 0 or 1 (mod 5).
(d) If the integer a is not divisible by 2 or 3, then a2 = 1 (mod 24).
9. If p is a prime satisfying n < p < 2n, show that
th
(:)-
= 0 (mod p)
10. If a1, a2, ..., an is a complete set of residues modulo n and gcd(a, n) = 1, prove that
ad¡, aa2, . , aa, is also a complete set of residues modulo n.
[Hint: It suffices to show that the numbers in question are incongruent modulo n.]
11. Verify that 0, 1, 2, 2², 2³,..., 2º form a complete set of residues modulo 11, but that
0, 12, 22, 3²,.., 10² do not.
12. Prove the following statements:
(a) If gcd(a, n) = 1, then the integers
c, c+a, c+ 2a, c + 3a, ... , c + (n – 1)a
form a complete set of residues modulo n for any c.
(b) Any n consecutive integers form a complete set of residues modulo n.
[Hint: Use part (a).]
(c) The product of any set of n consecutive integers is divisible by n.
13. Verify that if a = b (mod nj) and a = b (mod n2), then a = b (mod n), where the integer
n = lcm(n1, n2). Hence, whenever n¡ and n2 are relatively prime, a = b (mod n¡nɔ).
14. Give an example to show that a = b* (mod n) and k = j (mod n) need not imply that
ai = bi (mod n).
15. Establish that if a is an odd integer, then for any n > 1
a2"
= 1 (mod 2"+2)
[Hint: Proceed by induction on n.]
16. Use the theory of congruences to verify that
89| 244 1
97 | 248 1
and
17. Prove that whenever ab = cd (mod n) and b = d (mod n), with gcd(b, n) = 1. then
a =c (mod n).
n = gcd(n1, n2).
Transcribed Image Text:18. If a =b (mod n1) and a =c (mod n2), prove that b =c (mod n), where the integer (a) 7|52n +3-2 5n –2 (b) 13|3"+2 + 42n+1. (c) 27|25n+1 + 5n+2_ (d) 43 6+2 +72n+1. 7. For n > 1, show that 4.3 One spec hear to in (-13)"+1 = (-13)" + (-13)"- (mod 181) sys inte [Hint: Notice that (-13)2 = -13 +1 (mod 181); use induction on n.] 8. Prove the assertions below: (a) If a is an odd integer, then a? = 1 (mod 8). (b) For any integer a, a³ = 0, 1, or 6 (mod 7). (c) For any integer a, a* = 0 or 1 (mod 5). (d) If the integer a is not divisible by 2 or 3, then a2 = 1 (mod 24). 9. If p is a prime satisfying n < p < 2n, show that th (:)- = 0 (mod p) 10. If a1, a2, ..., an is a complete set of residues modulo n and gcd(a, n) = 1, prove that ad¡, aa2, . , aa, is also a complete set of residues modulo n. [Hint: It suffices to show that the numbers in question are incongruent modulo n.] 11. Verify that 0, 1, 2, 2², 2³,..., 2º form a complete set of residues modulo 11, but that 0, 12, 22, 3²,.., 10² do not. 12. Prove the following statements: (a) If gcd(a, n) = 1, then the integers c, c+a, c+ 2a, c + 3a, ... , c + (n – 1)a form a complete set of residues modulo n for any c. (b) Any n consecutive integers form a complete set of residues modulo n. [Hint: Use part (a).] (c) The product of any set of n consecutive integers is divisible by n. 13. Verify that if a = b (mod nj) and a = b (mod n2), then a = b (mod n), where the integer n = lcm(n1, n2). Hence, whenever n¡ and n2 are relatively prime, a = b (mod n¡nɔ). 14. Give an example to show that a = b* (mod n) and k = j (mod n) need not imply that ai = bi (mod n). 15. Establish that if a is an odd integer, then for any n > 1 a2" = 1 (mod 2"+2) [Hint: Proceed by induction on n.] 16. Use the theory of congruences to verify that 89| 244 1 97 | 248 1 and 17. Prove that whenever ab = cd (mod n) and b = d (mod n), with gcd(b, n) = 1. then a =c (mod n). n = gcd(n1, n2).
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