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To iuruior uxplain the topic on Point and Interval Estimation, you may click/visit these links: https.///www.voutube.com/watchvavwzo--eosk hittes.//www.youtube.com/watch DTPGOHM A. Find a in the following confidence level. 1. 88% B. Find the Critical Value z that corresponds to the given confidence level. 2. 96% C. Find the mean height of the Students 3. The following are students. the heights in centimeters of 15 randomly selected 167 160 160 170 162 165 165 154 160 162 167 163 157 166 160 D. Find the margin of error 4. 9,920.51 < ju < 10,079.49 E. Find the margin of error E 5. Confidence level: 95% a 0.60 n= 44 F. Find the 99% confidence interval of a population mean u for the following values 6. n 49, * 72 O = 0.78 Teacher's Notes:

To iuruior uxplain the topic on Point and Interval Estimation, you may click/visit these links: https.///www.voutube.com/watchvavwzo--eosk hittes.//www.youtube.com/watch DTPGOHM A. Find a in the following confidence level. 1. 88% B. Find the Critical Value z that corresponds to the given confidence level. 2. 96% C. Find the mean height of the Students 3. The following are students. the heights in centimeters of 15 randomly selected 167 160 160 170 162 165 165 154 160 162 167 163 157 166 160 D. Find the margin of error 4. 9,920.51 < ju < 10,079.49 E. Find the margin of error E 5. Confidence level: 95% a 0.60 n= 44 F. Find the 99% confidence interval of a population mean u for the following values 6. n 49, * 72 O = 0.78 Teacher's Notes:

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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This is due in an hour please help me solve it, I badly needed this for my mid term. Thank you

? 1o further explain the topic on Point and Interval Estimation, you may click/visit these links: https:///www.voutube.com/watchvavwzo-t-eosk https//www.youtube.com/watchyDT-IPGOHT A. Find a in the following confidence level. 1. 88% B. Find the Critical Value ze that corresponds to the given confidence level. 2. 96% Solve the problem then sketch the 1. Consider the normal distributio C. Find the mean height of the Students 167 160 170 160 162 160 165 165 162 154 167 163 157 166 160 of 16. What percentage of IQ's a. Greater than 95? the heights in centimeters of 15 randomly selected 3. The following are students, b. Less than 120? c. Between 90 and 110? 2. There were a total of 15 master's examination. Their scores are give D. Find the margin of error 4. 9,920.51 < a < 10,079.49 E. Find the margin of error E 5. Confidence level : 95% a = 0.60 n= 44 93 78 F. Find the 99% confidence interval of a population mean u for the following values 6. n= 49, 81 85 a = 0.78 ute the fol *= 72 88 Teacher's Notes:
Transcribed Image Text:? 1o further explain the topic on Point and Interval Estimation, you may click/visit these links: https:///www.voutube.com/watchvavwzo-t-eosk https//www.youtube.com/watchyDT-IPGOHT A. Find a in the following confidence level. 1. 88% B. Find the Critical Value ze that corresponds to the given confidence level. 2. 96% Solve the problem then sketch the 1. Consider the normal distributio C. Find the mean height of the Students 167 160 170 160 162 160 165 165 162 154 167 163 157 166 160 of 16. What percentage of IQ's a. Greater than 95? the heights in centimeters of 15 randomly selected 3. The following are students, b. Less than 120? c. Between 90 and 110? 2. There were a total of 15 master's examination. Their scores are give D. Find the margin of error 4. 9,920.51 < a < 10,079.49 E. Find the margin of error E 5. Confidence level : 95% a = 0.60 n= 44 93 78 F. Find the 99% confidence interval of a population mean u for the following values 6. n= 49, 81 85 a = 0.78 ute the fol *= 72 88 Teacher's Notes:
p=0.99 p = 0.95 area to the left of t, b. t represents the 99th percentile to.99 c. To find the value of t1, look at 18 under column headed df. Proceed to the right until the column headed 0.01 for one tail is reached. The result is 2.552. npute the following: opulation Mean pulation Variance To further explain the topic on t- Distribution, you may click/visit these links: https://www.voutube com/watch?v=OaiLoJdsEyc https://www.voutube com/watch?v=MUD390|tgQs ulation Standard Deviatic Schec A. Find the following t- values in the Table of t- Critical Values. 1. to.os for df =8 2. to.025 for df = 15 %3D B. Find the critical values of t when the area of the right hand tail of the t-distribution is 0.05 given the following degrees of freedom (df). 3. 6 4. 15 C. Find the critical values of twhen the area of the right hand tail of the t-distribution is 0.10 given the following (df). 5. 7 6. 17
Transcribed Image Text:p=0.99 p = 0.95 area to the left of t, b. t represents the 99th percentile to.99 c. To find the value of t1, look at 18 under column headed df. Proceed to the right until the column headed 0.01 for one tail is reached. The result is 2.552. npute the following: opulation Mean pulation Variance To further explain the topic on t- Distribution, you may click/visit these links: https://www.voutube com/watch?v=OaiLoJdsEyc https://www.voutube com/watch?v=MUD390|tgQs ulation Standard Deviatic Schec A. Find the following t- values in the Table of t- Critical Values. 1. to.os for df =8 2. to.025 for df = 15 %3D B. Find the critical values of t when the area of the right hand tail of the t-distribution is 0.05 given the following degrees of freedom (df). 3. 6 4. 15 C. Find the critical values of twhen the area of the right hand tail of the t-distribution is 0.10 given the following (df). 5. 7 6. 17
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