To get the integrating factor of ædy + ydr – 4 + = 0. ! = you have rewrite the equation. (make sure to make the left side of the equation zero)ædy + ydx Then follow the format M(x,y)dx+N(x,y)%Y3D0 (y -) dæ + (x + ) dy = 0 Then perform partial derivatives SM 1+ Sy SN 1 1 SM SN There fore Nom – Exact Sy In this problem using case 1, the f(x) is not in terms of x alone using case 2, the g(y) is not in terms of y alone so we must use case 3. According to case 3: If Sy &M &N = m (4), then x"y" is an integrating factor of M (x, y) + N (x, y) = 0 - n Substitute the given: 1+8-(1-2)-"(뿌) -"(부) = m n | simplify the equation: "(1+ )-" (1-급) 1 = m distribute the m and n 1 .+글 = m+m n+n (주) ||

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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To get the integrating factor of ædy + ydx
+ = 0.
you have rewrite the equation. (make sure to make the left side of the equation zero)ædy + ydx
Then follow the format M(x,y)dx+N(x,y)dy3D0
(y-1) dz + (z+ 글) dy = 0
Then perform partial derivatives
SM
1+
Sy
SN
= 1
Sz
SM
, There fore Non
Exact
In this problem
using case 1, the f(x) is not in terms of x alone
using case 2, the g(y) is not in terms of y alone
so we must use case 3.
According to case 3:
If SM
() - n (M), then r"y" is an integrating factor of M (x, y) + N (x, y) = 0
= m
Substitute the given:
1+3-(1-3)-m(부)-"(부)
= m
simplify the equation:
*+= m
(주 -1) u- (두 + 1) 4
distribute them and n
= m + m
- n+n
(주)"
equate the coefficient of
1= n
equate the coefficient of -
1=m
therefore u (x) = x™y" = xy
Transcribed Image Text:To get the integrating factor of ædy + ydx + = 0. you have rewrite the equation. (make sure to make the left side of the equation zero)ædy + ydx Then follow the format M(x,y)dx+N(x,y)dy3D0 (y-1) dz + (z+ 글) dy = 0 Then perform partial derivatives SM 1+ Sy SN = 1 Sz SM , There fore Non Exact In this problem using case 1, the f(x) is not in terms of x alone using case 2, the g(y) is not in terms of y alone so we must use case 3. According to case 3: If SM () - n (M), then r"y" is an integrating factor of M (x, y) + N (x, y) = 0 = m Substitute the given: 1+3-(1-3)-m(부)-"(부) = m simplify the equation: *+= m (주 -1) u- (두 + 1) 4 distribute them and n = m + m - n+n (주)" equate the coefficient of 1= n equate the coefficient of - 1=m therefore u (x) = x™y" = xy
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