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To find the speed of rocket when it to determine time at We need which t = h(t) = 0 - 4.9+² +17² +0.8=0 The quadratic equation ax ² +bx+c=0 a= -4.9, 6=17, C = 0.8 db dt - b ± √b²-4ac 20 dh at 13.5 when it hits the - 9.8t +17 〃 it hits. -17 ± √ (17) ² -4 (-4.9) (0.8) 2 (-409) 17 ± 304.68 -9.8 = -0.0464 -9.8 (3.5) +17 3.5158 ground, = -34.3 +17 = -17.3 m/s

To find the speed of rocket when it to determine time at We need which t = h(t) = 0 - 4.9+² +17² +0.8=0 The quadratic equation ax ² +bx+c=0 a= -4.9, 6=17, C = 0.8 db dt - b ± √b²-4ac 20 dh at 13.5 when it hits the - 9.8t +17 〃 it hits. -17 ± √ (17) ² -4 (-4.9) (0.8) 2 (-409) 17 ± 304.68 -9.8 = -0.0464 -9.8 (3.5) +17 3.5158 ground, = -34.3 +17 = -17.3 m/s

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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To find the speed of rocket when it to determine time at We need which t = h(t) = 0 - 4.9+² +17² +0.8=0 The quadratic equation ax ² +bx+c=0 a= -4.9, 6=17, C = 0.8 db dt - b ± √b²-4ac 20 dh at 13.5 when it hits the - 9.8t +17 〃 it hits. -17 ± √ (17) ² -4 (-4.9) (0.8) 2 (-409) 17 ± 304.68 -9.8 = -0.0464 -9.8 (3.5) +17 3.5158 ground, = -34.3 +17 = -17.3 m/s
Transcribed Image Text:To find the speed of rocket when it to determine time at We need which t = h(t) = 0 - 4.9+² +17² +0.8=0 The quadratic equation ax ² +bx+c=0 a= -4.9, 6=17, C = 0.8 db dt - b ± √b²-4ac 20 dh at 13.5 when it hits the - 9.8t +17 〃 it hits. -17 ± √ (17) ² -4 (-4.9) (0.8) 2 (-409) 17 ± 304.68 -9.8 = -0.0464 -9.8 (3.5) +17 3.5158 ground, = -34.3 +17 = -17.3 m/s
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