To find the distance from the house at A to the house at B, a surveyor measures the angle ACB, which is found to be 50°, and then walks off the distance to each house, 40 feet and 80 feet, respectively. How far apart are the houses? 80 ft 40 ft 50° The houses are feet apart. (Round to the nearest hundredth as needed.)

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
Question
To find the distance from the house at A to the house at B, a sureyor measures the angle ACB, which is found to be
50°, and then walks off the distance to each house, 40 feet and 80 feet, respectively. How far apart are the houses?
80 ft
40 ft
50
The houses are feet apart.
(Round to the nearest hundredth as needed.)
More
Enter your answer in the answer box.
Save for Later
Transcribed Image Text:To find the distance from the house at A to the house at B, a sureyor measures the angle ACB, which is found to be 50°, and then walks off the distance to each house, 40 feet and 80 feet, respectively. How far apart are the houses? 80 ft 40 ft 50 The houses are feet apart. (Round to the nearest hundredth as needed.) More Enter your answer in the answer box. Save for Later
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