To find the daily optimum production number of Portland cement in a factory, one needs to solve the following equations based on the ingredient of cement. The unknowns are lime, x1; silica, x2; alumina, x3; and iron oxide, X4. 10x1 – x2 + 2x3 = 6 -x1 + 11x2 – x3 + 3x4 = 25 2x1 – x2 + 10x3 – X4 = -11 Зx, — хз + 8х, 3 15 Use the Gauss-Seidel iterative technique to find approximate solutions to x1, X2, X3, and x4. Starting with x = (0, 0, 0, 0)" and iterating until max{]x(*+1) – x(k)} < e = 0.0005
To find the daily optimum production number of Portland cement in a factory, one needs to solve the following equations based on the ingredient of cement. The unknowns are lime, x1; silica, x2; alumina, x3; and iron oxide, X4. 10x1 – x2 + 2x3 = 6 -x1 + 11x2 – x3 + 3x4 = 25 2x1 – x2 + 10x3 – X4 = -11 Зx, — хз + 8х, 3 15 Use the Gauss-Seidel iterative technique to find approximate solutions to x1, X2, X3, and x4. Starting with x = (0, 0, 0, 0)" and iterating until max{]x(*+1) – x(k)} < e = 0.0005
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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pls ans soon
![(b)
To find the daily optimum production number of Portland cement in a
factory, one needs to solve the following equations based on the ingredient
of cement. The unknowns are lime, X1; silica, x2; alumina, x3; and iron oxide,
X4.
10х1 — х2 + 2хз 3D6
-x1 + 11x2 – X3 + 3x4 = 25
2х, — х2 + 10хз — х, 3D —11
Зx2 — хз + 8х, 3D 15
Use the Gauss-Seidel iterative technique to find approximate solutions to X1,
X2, X3, and x4. Starting with x = (0, 0, 0, 0)" and iterating until
max{|x(*+1) – x«*)} < e = 0.0005](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe49e1edb-efb1-442f-a9f4-a6ff010dad97%2Fb40ea6bd-90fa-4dd4-bc23-9350751bc316%2Fc556d5i_processed.png&w=3840&q=75)
Transcribed Image Text:(b)
To find the daily optimum production number of Portland cement in a
factory, one needs to solve the following equations based on the ingredient
of cement. The unknowns are lime, X1; silica, x2; alumina, x3; and iron oxide,
X4.
10х1 — х2 + 2хз 3D6
-x1 + 11x2 – X3 + 3x4 = 25
2х, — х2 + 10хз — х, 3D —11
Зx2 — хз + 8х, 3D 15
Use the Gauss-Seidel iterative technique to find approximate solutions to X1,
X2, X3, and x4. Starting with x = (0, 0, 0, 0)" and iterating until
max{|x(*+1) – x«*)} < e = 0.0005
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