To find a, vo, and so in the position equation s = (1/2)at2 + Vot + So for an object at the given heights moving vertically at the specified times shown below ,which system shown to the right would we use? A) a + 6vo + 2So = 100 4a + 2vo + 2so = 66 9a + 6vo + 2So = 132 At t=1 sec, s= 50 ft At t= 2 sec, s= 66 ft At t=3 sec, s= 50 ft B) a + 6vo + 2so = 100 4a + 6vo + 2so = 66 Ao s bivib o bo 9a + 6vo + 2so =100 C) a +2vo + 2so = 100 4a + 4vo + 2so = 132 9a + 6vo + 2so = 100 D) a+ 2vo+ 2so = 100 4a + 6vo + 2so =132 9a + 4vo + 2So =100 a E (G E) a + 2vo + 2so = 100 4a + 4vo + 2So = 132 9a + 6vo + 4so = 100
To find a, vo, and so in the position equation s = (1/2)at2 + Vot + So for an object at the given heights moving vertically at the specified times shown below ,which system shown to the right would we use? A) a + 6vo + 2So = 100 4a + 2vo + 2so = 66 9a + 6vo + 2So = 132 At t=1 sec, s= 50 ft At t= 2 sec, s= 66 ft At t=3 sec, s= 50 ft B) a + 6vo + 2so = 100 4a + 6vo + 2so = 66 Ao s bivib o bo 9a + 6vo + 2so =100 C) a +2vo + 2so = 100 4a + 4vo + 2so = 132 9a + 6vo + 2so = 100 D) a+ 2vo+ 2so = 100 4a + 6vo + 2so =132 9a + 4vo + 2So =100 a E (G E) a + 2vo + 2so = 100 4a + 4vo + 2So = 132 9a + 6vo + 4so = 100
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Transcribed Image Text:To find a, vo, and so in the position equation s (1/2)at2 + Vot + So for
an object at the given heights moving vertically at the specified times
shown below ,which system shown to the right would we use?
A) a + 6vo + 2so = 100
4a + 2vo + 2so = 66
%3D
9a + 6vo + 2so = 132
B) a+ 6vo + 2so = 100
4a + 6vo + 2so = 66
At t=1 sec,
s = 50 ft
At t=2 sec, s= 66 ft
At t=3 sec, s= 50 ft
%3D
%3D
9a + 6vo + 2so =100
SAT
C) a+ 2vo + 2So = 100
4a + 4vo + 2so = 132
9a + 6vo + 2so = 100
Vo
D) a+ 2vo + 2so = 100
4a + 6vo + 2so =132
9a + 4vo + 2so =100
%3D
E) a + 2vo + 2so = 100
4a + 4vo + 2s0 = 132
%3D
%3D
9a + 6vo + 4so = 100
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