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To estimate the amount of lumber in a tract of timber, an owner randomly selected seventy 50-by-50-foot squares, and counted the number of trees with diameters exceeding 12 inches in each square. The data are listed here. 8 Frequency 10 4 9 8 7 10 8 8 10 5 0.40 0.35 0.30 0.25 0205 5 9 10 5 8 16 4 5 8 8 10 8 10 7 9 4 LAUSE SALT 3 10 10 7 7 6 8 7 10 7 4 8 7 6 7 7 9 8 5 11 7 9 9 8 8 8 8 9 997 6 7 10 7 10 14 (a) Construct a relative frequency histogram to describe the data. Frequency of lumber 8 7 5 10 8 Frequency 0.40 0.35 0.30 0.25 0.20 Frequency of lumber e Frequency 0.40 0.35 0.30 0.25 0.20 Frequency of lumber H

To estimate the amount of lumber in a tract of timber, an owner randomly selected seventy 50-by-50-foot squares, and counted the number of trees with diameters exceeding 12 inches in each square. The data are listed here. 8 Frequency 10 4 9 8 7 10 8 8 10 5 0.40 0.35 0.30 0.25 0205 5 9 10 5 8 16 4 5 8 8 10 8 10 7 9 4 LAUSE SALT 3 10 10 7 7 6 8 7 10 7 4 8 7 6 7 7 9 8 5 11 7 9 9 8 8 8 8 9 997 6 7 10 7 10 14 (a) Construct a relative frequency histogram to describe the data. Frequency of lumber 8 7 5 10 8 Frequency 0.40 0.35 0.30 0.25 0.20 Frequency of lumber e Frequency 0.40 0.35 0.30 0.25 0.20 Frequency of lumber H

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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To estimate the amount of lumber in a tract of timber, an owner randomly selected seventy 50-by-50-foot squares, and counted the number of trees with diameters exceeding 12 inches in each square. The data are listed here. 8 Live Frequency 10 4 9 8 7 10 8 0.40 0.35 0.30 0.25 0.20 0.15 8 5 5 9 1 10 5 8 5 10 6 8 4 8 10 8 10 7 9 4 USE SALT 3 10 10 7 7 6 7 10 7 4 8 7 6 7 7 11 9 10 8 8 7 9 8 5 9 9 8 8 78 сл 7 10 9 8 9 7 7 6 14 (a) Construct a relative frequency histogram to describe the data. Frequency of lumber 10 8 ative Frequency 0.40 0.35 0.30 0.25 0.20 0.15 Frequency of lumber ative Frequency 0.40 0.35 0.30 0.25 0.20 0.15 10 Frequency of lumber
Transcribed Image Text:To estimate the amount of lumber in a tract of timber, an owner randomly selected seventy 50-by-50-foot squares, and counted the number of trees with diameters exceeding 12 inches in each square. The data are listed here. 8 Live Frequency 10 4 9 8 7 10 8 0.40 0.35 0.30 0.25 0.20 0.15 8 5 5 9 1 10 5 8 5 10 6 8 4 8 10 8 10 7 9 4 USE SALT 3 10 10 7 7 6 7 10 7 4 8 7 6 7 7 11 9 10 8 8 7 9 8 5 9 9 8 8 78 сл 7 10 9 8 9 7 7 6 14 (a) Construct a relative frequency histogram to describe the data. Frequency of lumber 10 8 ative Frequency 0.40 0.35 0.30 0.25 0.20 0.15 Frequency of lumber ative Frequency 0.40 0.35 0.30 0.25 0.20 0.15 10 Frequency of lumber
(b) Calculate the sample mean x as an estimate of u, the mean number of trees for all 50-by-50-foot squares in the tract. (Round your answer to three decimal places.) X = 7.6286 timber trees (c) Calculates for the data. (Round your answer to three decimal places.) S = 2.1344 timber trees Construct the intervals x ± s, x ± 2s, and x ± 3s. Calculate the percentage of squares falling into each of the three intervals, and compare with the corresponding percentages given by the Empirical Rule and Tchebysheff's Theorem. (Round your interval values to three decimal places. Round actual percentages to two decimal places.) X+S x + 2s x + 3s Interval 3.360 to. 1.225 to to 9.763 Actual Percentage % % % Tchebysheff at least at least 75% at least 89% % ≈ Empirical ≈ 68% ≈ 99.7% %
Transcribed Image Text:(b) Calculate the sample mean x as an estimate of u, the mean number of trees for all 50-by-50-foot squares in the tract. (Round your answer to three decimal places.) X = 7.6286 timber trees (c) Calculates for the data. (Round your answer to three decimal places.) S = 2.1344 timber trees Construct the intervals x ± s, x ± 2s, and x ± 3s. Calculate the percentage of squares falling into each of the three intervals, and compare with the corresponding percentages given by the Empirical Rule and Tchebysheff's Theorem. (Round your interval values to three decimal places. Round actual percentages to two decimal places.) X+S x + 2s x + 3s Interval 3.360 to. 1.225 to to 9.763 Actual Percentage % % % Tchebysheff at least at least 75% at least 89% % ≈ Empirical ≈ 68% ≈ 99.7% %
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