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To determine the reaction forces at supports on a horizontal beam by using the equations of equilibrium for a static application. As shown, beam ABC is supported by the roller at A and pin at C. The geometry of the beam is given by a = 5.0 m, b = 6.5 m, and c = 11.0 m. The applied forces are F = 2.75 kN and F2 = 2.00 kN. Force F, is applied at an angle 0 = 60° with the horizontal. Neglect the weight of the beam. (Figure 1) Figure 1 of 1 y F1 В F2

To determine the reaction forces at supports on a horizontal beam by using the equations of equilibrium for a static application. As shown, beam ABC is supported by the roller at A and pin at C. The geometry of the beam is given by a = 5.0 m, b = 6.5 m, and c = 11.0 m. The applied forces are F = 2.75 kN and F2 = 2.00 kN. Force F, is applied at an angle 0 = 60° with the horizontal. Neglect the weight of the beam. (Figure 1) Figure 1 of 1 y F1 В F2

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Determine the horizontal component of the pin reaction at C.

Learning Goal: To determine the reaction forces at supports on a horizontal beam by using the equations of equilibrium for a static application. As shown, beam ABC is supported by the roller at A and pin at C. The geometry of the beam is given by a = 5.0 m, b= 6.5 m, and c = 11.0 m. The applied forces are Fi = 2.75 kN and F2 = 2.00 kN. Force Fi is applied at an angle e = 60° with the horizontal. Neglect the weight of the beam. (Figure 1) Figure < 1 of 1 y L. b F1 В a F2
Transcribed Image Text:Learning Goal: To determine the reaction forces at supports on a horizontal beam by using the equations of equilibrium for a static application. As shown, beam ABC is supported by the roller at A and pin at C. The geometry of the beam is given by a = 5.0 m, b= 6.5 m, and c = 11.0 m. The applied forces are Fi = 2.75 kN and F2 = 2.00 kN. Force Fi is applied at an angle e = 60° with the horizontal. Neglect the weight of the beam. (Figure 1) Figure < 1 of 1 y L. b F1 В a F2
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