To determine the organic material in a dried lake bed, the percent carbon by mass is measured at two different locations. To compare the means of the two different locations, it must first be determined whether the standard deviations of the two locations Location 1 (% Location 2 (% Sample C) C) 60.40 60.10 are different. 2 60.20 60.90 For each location, calculate the standard deviation and report it with two significant figures. 3 60.30 60.20 60.40 60.70 60.20 60.30 location 1 standard deviation: 0.01 location 2 standard deviation: 0.12 What is the calculated F value for comparing the standard deviations? Feale = 144 4. 5.
To determine the organic material in a dried lake bed, the percent carbon by mass is measured at two different locations. To compare the means of the two different locations, it must first be determined whether the standard deviations of the two locations Location 1 (% Location 2 (% Sample C) C) 60.40 60.10 are different. 2 60.20 60.90 For each location, calculate the standard deviation and report it with two significant figures. 3 60.30 60.20 60.40 60.70 60.20 60.30 location 1 standard deviation: 0.01 location 2 standard deviation: 0.12 What is the calculated F value for comparing the standard deviations? Feale = 144 4. 5.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![To determine the organic material in a dried lake bed, the percent carbon by mass is measured at two different locations. To compare the means of the two different locations, it must first be determined whether the standard deviations of the two locations are different.
For each location, calculate the standard deviation and report it with two significant figures.
Table:
```
| Sample | Location 1 (% C) | Location 2 (% C) |
|--------|------------------|------------------|
| 1 | 60.40 | 60.10 |
| 2 | 60.20 | 60.90 |
| 3 | 60.30 | 60.70 |
| 4 | 60.40 | 60.70 |
| 5 | 60.20 | 60.30 |
```
### Calculations:
- **Location 1 standard deviation:** 0.01
- **Location 2 standard deviation:** 0.12
### Comparison of Standard Deviations:
- **What is the calculated F value for comparing the standard deviations?**
- \( F_{\text{calc}} = 144 \)
### Conclusion:
- **Are the standard deviations for the two locations significantly different at the 95% confidence level?**
- [Answer will depend on further statistical analysis based on F-distribution tables, not provided in the current context.]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc6184893-1e67-4ed8-9784-fdd0cf2ed60a%2Fc2e07435-ea19-4023-b064-2e7904f2933a%2F6posqtb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:To determine the organic material in a dried lake bed, the percent carbon by mass is measured at two different locations. To compare the means of the two different locations, it must first be determined whether the standard deviations of the two locations are different.
For each location, calculate the standard deviation and report it with two significant figures.
Table:
```
| Sample | Location 1 (% C) | Location 2 (% C) |
|--------|------------------|------------------|
| 1 | 60.40 | 60.10 |
| 2 | 60.20 | 60.90 |
| 3 | 60.30 | 60.70 |
| 4 | 60.40 | 60.70 |
| 5 | 60.20 | 60.30 |
```
### Calculations:
- **Location 1 standard deviation:** 0.01
- **Location 2 standard deviation:** 0.12
### Comparison of Standard Deviations:
- **What is the calculated F value for comparing the standard deviations?**
- \( F_{\text{calc}} = 144 \)
### Conclusion:
- **Are the standard deviations for the two locations significantly different at the 95% confidence level?**
- [Answer will depend on further statistical analysis based on F-distribution tables, not provided in the current context.]
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