To create the graph of the derivative we have to remember that "the y-value of each point on the graph of the derivative is the slope of the tangent line at a particular x-value." Use the chart above to find points of the derivative graph. Fill in table and use these points to sketch f'(x).[The first two are done for Points on X-values Point on f'(x) you] Slope of y 10 f(x) = x2 tangent line at x 2X value (-3,9) -3 -6 (3,-6) (-2.48, 6.16) -2.48 -4.96 (-2.48, -4.96) (-2,4) -2 ( u) (-1.54,2.38)-ル5u308 (-1,1) -2 -1 10:0 1 (0,0) (0.68,0.47) 0.68 1.36 2. 136 ,2 (1,1) 1. (2,4) 2. (2.24,5.01) 2.24 (3,9) 3.
To create the graph of the derivative we have to remember that "the y-value of each point on the graph of the derivative is the slope of the tangent line at a particular x-value." Use the chart above to find points of the derivative graph. Fill in table and use these points to sketch f'(x).[The first two are done for Points on X-values Point on f'(x) you] Slope of y 10 f(x) = x2 tangent line at x 2X value (-3,9) -3 -6 (3,-6) (-2.48, 6.16) -2.48 -4.96 (-2.48, -4.96) (-2,4) -2 ( u) (-1.54,2.38)-ル5u308 (-1,1) -2 -1 10:0 1 (0,0) (0.68,0.47) 0.68 1.36 2. 136 ,2 (1,1) 1. (2,4) 2. (2.24,5.01) 2.24 (3,9) 3.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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How should the graph look like here?
![To create the graph of the derivative we have to remember that "the y-value of each point on the graph
of the derivative is the slope of the tangent line at a particular x-value." Use the chart above to find
points of the derivative graph. Fill in table and use these points to sketch f'(x).[The first two are done for
Points on
X-values
Slope of
Point on f'(x)
you]
10
f(x) = x2
tangent
line at x
2X
value
(-3,9)
-3
-6
(3,-6)
(-2.48, 6.16)
-2.48
-4.96
(-2.48, -4.96)
(-2,4)
-2
(-1.54,2.38)-ル5u308
(-1,1)
7 8
-1
10,01
136
(0,0)
(0.68,0.47)
0.68 1.36
2.
(1,1)
1.
(2,4)
2.
(2.24,5.01)
2-24
(3,9)
3.
1.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbef9531f-0183-4bae-9af8-c39303b943fa%2F847d5fa3-d659-4700-9a8b-6ee7301cfc42%2Fk0m5td7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:To create the graph of the derivative we have to remember that "the y-value of each point on the graph
of the derivative is the slope of the tangent line at a particular x-value." Use the chart above to find
points of the derivative graph. Fill in table and use these points to sketch f'(x).[The first two are done for
Points on
X-values
Slope of
Point on f'(x)
you]
10
f(x) = x2
tangent
line at x
2X
value
(-3,9)
-3
-6
(3,-6)
(-2.48, 6.16)
-2.48
-4.96
(-2.48, -4.96)
(-2,4)
-2
(-1.54,2.38)-ル5u308
(-1,1)
7 8
-1
10,01
136
(0,0)
(0.68,0.47)
0.68 1.36
2.
(1,1)
1.
(2,4)
2.
(2.24,5.01)
2-24
(3,9)
3.
1.
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