To begin evaluating | sin*xcos xdx conveniently , express: A) None B sin*x as (sin?x)²and use the Half - Angle Formula sin²x=÷(1- sin sin*x as (sin?x)2and use the identity sin?x=1- cos?x (D cos x as (cos?x)²cosx and use the identity cos²x=1- sin²x cos x as (cos?x)?cosx and use the Half – Angle Formula cos²x=-(1+cos2x) 2
To begin evaluating | sin*xcos xdx conveniently , express: A) None B sin*x as (sin?x)²and use the Half - Angle Formula sin²x=÷(1- sin sin*x as (sin?x)2and use the identity sin?x=1- cos?x (D cos x as (cos?x)²cosx and use the identity cos²x=1- sin²x cos x as (cos?x)?cosx and use the Half – Angle Formula cos²x=-(1+cos2x) 2
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 10E
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Question
![To begin evaluating | sin*xcos xdx conveniently , express:
S.
A None
B
sintx as (sin?x)?and use the Half – Angle Formula sin?x=-(1- sin²2x)
2
sin*x as (sin²x)²and use the identity sin²x=1- cos?x
D)
cos x as
(cos?x) ?cosx and use the identity cos?x=1- sin?x
E cos x as (cos?x)²cosx and use the Half – Angle Formula cos?x=
1+ cos2r)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F050a8e60-5adf-4960-9a0a-6e95b65b4ed7%2F4123e75c-e38b-4adc-9144-0a2b39d10fee%2Fu6x4570c_processed.png&w=3840&q=75)
Transcribed Image Text:To begin evaluating | sin*xcos xdx conveniently , express:
S.
A None
B
sintx as (sin?x)?and use the Half – Angle Formula sin?x=-(1- sin²2x)
2
sin*x as (sin²x)²and use the identity sin²x=1- cos?x
D)
cos x as
(cos?x) ?cosx and use the identity cos?x=1- sin?x
E cos x as (cos?x)²cosx and use the Half – Angle Formula cos?x=
1+ cos2r)
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